If inside of for loop is not working
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This is my reference code, it is working well. g is a 96 x 1 cell.
k = 1;
dx = (65-45)/4; dy = 120/24;
y1 = 0; y2 = y1 + dy; x1 = 45; x2 = x1 + dx;
while y1 <= 120 && x2 <= 65
g{k} = [x1 x2 y1 y2];
y1 = y1 + dy; y2 = y2 + dy;
k = k + 1;
if y1 == 120
y1 = 0; y2 = y1 + dy; x1 = x1 + dx; x2 = x2 + dx;
end
end
g = g';
But this code does not give the correct answer, g should be a 40x1 cell but it gave me 11x1 cell
k = 1;
dx = (3-0)/4; dy = 1/10;
y1 = 0; y2 = y1 + dy; x1 = 0; x2 = x1 + dx;
while y1 <=1 && x2 <=3
g{k} = [x1 x2 y1 y2];
y1 = y1 + dy; y2 = y2 + dy;
k = k + 1;
if y1 == 1
y1 = 0; y2 = y1 + dy; x1 = x1 + dx; x2 = x2 + dx;
end
end
g = g';
Any idea where I did wrong?
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Chunru
le 23 Août 2022
k = 1;
dx = (3-0)/4; dy = 1/10;
y1 = 0; y2 = y1 + dy; x1 = 0; x2 = x1 + dx;
while y1 <=1 && x2 <=3
%[k, y1, x2]
g{k} = [x1 x2 y1 y2];
y1 = y1 + dy; y2 = y2 + dy;
k = k + 1;
% Due to the floating point rounding error, y1 == 1 is never be true
% for this code. Make change as follows:
if abs(y1 - 1) < 1e-10
y1 = 0; y2 = y1 + dy; x1 = x1 + dx; x2 = x2 + dx;
end
end
g = g'
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