I have a matrix.
A=[1 2 3 4 5 6 7 8]
I want to separate the alternate elemets from the array.
I tried to do this,
N=[1 2 3 4 5 6 7 8];
Th1=zeros(4,0);
Th2=zeros(4,0);
for i=1:1:8
if mod(i,2)==0;
Th1=N(i);
else
Th2=N(i);
end
end
I am sure solution must be very simple. But, the code seems to save only the last values. Any help?

 Réponse acceptée

A = [1,2,3,4,5,6,7,8];
X = A(1:2:end)
X = 1×4
1 3 5 7
Y = A(2:2:end)
Y = 1×4
2 4 6 8

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