How do I square an array?

76 vues (au cours des 30 derniers jours)
Danielle Brunig
Danielle Brunig le 29 Août 2022
Hi, I'm trying to square an array, but it won't work for some reason, and I cannot figure out why. I'm sure I'm probably overlooking something big though.
x=[a:10:b];
y=x.^2;
gz=-0.2794*(p)*(r^3)*z/((y+z^2)^(3/2))
It gives me multiple errors whenever I try to run this code through, even though I coded all of the variables, it doesn't like trying to square them.
  1 commentaire
Torsten
Torsten le 29 Août 2022
Modifié(e) : Torsten le 29 Août 2022
Please include the full code and write exactly what does not work.
In gz, you will of course have to use .^, .* and ./ instead of ^, * and /
x = 1:10;
y = x.^2
y = 1×10
1 4 9 16 25 36 49 64 81 100

Connectez-vous pour commenter.

Réponses (2)

Image Analyst
Image Analyst le 29 Août 2022
Modifié(e) : Image Analyst le 29 Août 2022
This works fine for me
% Define parameters
a = 10;
b = 40;
x=[a:10:b]
x = 1×4
10 20 30 40
y=x.^2
y = 1×4
100 400 900 1600
% Define parameters
p = 2;
r = 3;
z = 6;
gz=-0.2794*(p)*(r^3)*z ./ ((y+z.^2) .^ (3/2))
gz = 1×4
-0.0571 -0.0099 -0.0032 -0.0014
If you have any more questions, then attach your actual error message (ALL the red text) and data (actual parameters) and code to read it in with the paperclip icon after you read this:

Nisarg
Nisarg le 8 Mai 2024
class_intervals = [10, 20, 30, 40, 50];
frequencies = [5, 8, 12, 10, 6];
n = sum(frequencies)
mean = sum(class_intervals .* frequencies)/n
y = sum(frequencies.*((class_intervals - mean).^2))
std = sqrt(y/n)

Catégories

En savoir plus sur Matrix Indexing dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by