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Incorrect non restoring division for unsigned integers !!

9 vues (au cours des 30 derniers jours)
Life is Wonderful
Life is Wonderful le 6 Sep 2022
Modifié(e) : Yash le 12 Sep 2023
Hi there,
For unsigned integer values, I am attempting to construct a non-restoring division algorithm, but it appears that I am having difficulties getting the quotient and remainder right.
Can you give me some advice on how to improve the implementation?
Many thanks
n = 32;
N = 11;
D = 3;
R = zeros(1,1);
Q = 0;
D = bitshift(D, 1);
for i = 1 : (n-1) %.. 0 do -- for example 31..0 for 32 bits
if R >= 0
Q = accumpos(Q,1);
R = 2 * R - D;
Q = accumneg(Q,1);
R = 2 * R + D;
Q = Q - not(Q); % -- Appropriate if −1 digits in Q are represented as zeros as is common.
if R < 0
Q = accumneg(Q,1);
R = R + D; %-- Needed only if the remainder is of interest.
Q ,R
Q = -30
R = 0

Réponses (1)

Yash le 7 Sep 2023
Modifié(e) : Yash le 12 Sep 2023
I can understand that you are interested in implementing the non-restoring division for unsigned integers.
I have reviewed your code and noticed a few areas that require attention:
  1. The Most Significant Bit (MSB) of "Q" is should be assigned as the Least Significant Bit (LSB) of "R" while left shifting "RQ".
  2. After left shifting of "RQ", there should be a statement to update "R" based on its signed bit, either by adding or subtracting "D".
  3. After updating "R", the LSB of Q should be updated depending on the signed bit of R.
  4. Since this algorithm involves many bitwise operations like left shift, right shift, and bitwise assignment, it is recommended to use arrays to represent binary numbers instead of decimal numbers.
Kindly refer to the below example code snippet that demonstrates how to initialize the arrays using binary representations:
dividendBin = dec2bin(dividend);
divisorBin = dec2bin(divisor);
% Initialize the registers
A = zeros(1, numBits+1);
Q = zeros(1, numBits);
% Set the dividend and divisor in the registers
Q(end-length(dividendBin)+1:end) = dividendBin - '0';
M = [zeros(1, numBits - length(divisorBin)+1) divisorBin-'0'];
Refer the below code to implement the algorithm:
for i = 1:numBits
% Check signed bit of A
A0 = A(1);
%left Shift AQ
A = [A(2:end) Q(1)];
Q = [Q(2:end) 0];
if A0==0
A = addBin(A,negM);
A = addBin(A,M);
% Decide LSB of Q
quotient = bin2dec(num2str(Q));
remainder = bin2dec(num2str(A));
In the above example, "addBin" is a custom MATLAB function which adds two arrays containing binary representations, "negM" is the 2's complement of M.
To know more about the algorithm, I suggest you refer the following article: link.
I hope this helps you address the issue.
  1 commentaire
Life is Wonderful
Life is Wonderful le 12 Sep 2023
Please give me some time to acknowledge your efforts, . Thanks a lot @Yash

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