Convert integer value to a vector

I would like to convert the value 1101 to a 1x4 [1,1,0,1] in simulink

Answer 1

[Moe_2015]

You can do this by placing a matlab function block in Simulink. Your function should look like below. Connect your input signal (that has 1101) and the output will be a vector [1,1,0,1]

function vector = n_to_vector(n)
vector = num2str(n) - '0';
end

[Moe_2015]

You can test this in your matlab command window:

n = 1101;
vector = num2str(n) - '0'

vector = 1×4

1 1 0 1

[Adam s]

The function above gives this error

num2str is supported only for constant inputs. Consider using sprintf instead. Function 'SM_grid/MATLAB Function3' (#1110.42.52), line 2, column 10: "num2str(n)" Launch diagnostic report.

Component:MATLAB Function | Category:Coder error

Errors occurred during parsing of MATLAB function 'ssn_IEEE123_CompensatedStubline/SM_grid/MATLAB Function3'

Component:MATLAB Function | Category:Coder error

Simulink cannot determine sizes and/or types of the outputs for block 'ssn_IEEE123_CompensatedStubline/SM_grid/MATLAB Function3' due to errors in the block body, or limitations of the underlying analysis. The errors might be inaccurate. Fix the indicated errors, or explicitly specify sizes and/or types for all block outputs.

[Adam s]

changing num2str() to sprintf() returns a value of 62

[Moe_2015]

sorry I realize now that simulink may have trouble with this. I have tried the below in Simulink and it worked. I borrowed a different way to compute this from Jan located here: https://www.mathworks.com/matlabcentral/answers/155622-hi-guys-i-need-help-splitting-a-number-into-its-individual-parts-and-then-add-them-e-g-the-number#answer_382856

so make your function look as below. In Ports and Data Manager, you will need to select vector (which is your output from the block) and check the variable size box and make the Size [1 4]. Also, in the settings (gear icon Configuration Parameters), you need to change solver to Fixed-step

function vector = n_to_vector(n)
m = floor(log10(n));
vector = mod(floor(n ./ 10 .^ (m:-1:0)), 10);
end

[Walter Roberson]

assert(n >0 && n <= intmax('uint64'));

longest_possible_integer = 20;
charvec = blanks(longest_possible_integer);
vector = zeros(1, longest_possible_integer);

coder.varsize('charvec', 'vector', [1 longest_possible_integer]);
charvec = sprintf('%u', n);
vector = charvec - '0';

Here, longest_possible_integer = length(sprintf('%u', intmax('uint64'))) . Any input that is large magnitude than that will get converted in scientific notation by sprintf() and the process will fail