Changing for loop to backslash

How do I change this code to not have a for loop. Hint: one backslash with multiple right-hand sides, solved simultaneously.

% Create a matrix of the coefficients 
A = [6 -1 0 0 0; -3 3 0 0 0; 0 -1 9 0 0; 0 -1 -8 11 -2; -3 -1 0 0 4];

% Compute the LU Factorization
[L,U,P] = lu(A);

% Loop for each value of M from 10 to 100 with increments of 10
for M = 10 : 10 : 100
  
  % Create a column vector of right hand side values
  b = [M; 0; 160; 0; 0];
  
  % Use the factors from LU factorization to solve 
  % two triangular linear systems
  y = L\(P*b); 
  c = U\y;
  
  % Print the solution of system of equation for current value of M
  fprintf('\nSolution of system of equation for M = %d is\n', M);
  disp(c);
  
end

Solution of system of equation for M = 10 is

    2.0000
    2.0000
   18.0000
   13.6364
    2.0000

Solution of system of equation for M = 20 is

    4.0000
    4.0000
   18.2222
   14.3434
    4.0000

Solution of system of equation for M = 30 is

    6.0000
    6.0000
   18.4444
   15.0505
    6.0000

Solution of system of equation for M = 40 is

    8.0000
    8.0000
   18.6667
   15.7576
    8.0000

Solution of system of equation for M = 50 is

   10.0000
   10.0000
   18.8889
   16.4646
   10.0000

Solution of system of equation for M = 60 is

   12.0000
   12.0000
   19.1111
   17.1717
   12.0000

Solution of system of equation for M = 70 is

   14.0000
   14.0000
   19.3333
   17.8788
   14.0000

Solution of system of equation for M = 80 is

   16.0000
   16.0000
   19.5556
   18.5859
   16.0000

Solution of system of equation for M = 90 is

   18.0000
   18.0000
   19.7778
   19.2929
   18.0000

Solution of system of equation for M = 100 is

    20
    20
    20
    20
    20

Answer 1

[Torsten]

A = [6 -1 0 0 0; -3 3 0 0 0; 0 -1 9 0 0; 0 -1 -8 11 -2; -3 -1 0 0 4];
b = [10:10:100;repmat([0; 160; 0; 0],1,10)];
dA = decomposition(A);
tic
for i=1:100000
c = dA\b;
end
toc

Elapsed time is 0.341871 seconds.

or

A = [6 -1 0 0 0; -3 3 0 0 0; 0 -1 9 0 0; 0 -1 -8 11 -2; -3 -1 0 0 4];
b = [10:10:100;repmat([0; 160; 0; 0],1,10)];
[L,U,P] = lu(A);
tic
for i=1:100000
y = L\(P*b); 
c = U\y;
end
toc

Elapsed time is 0.282530 seconds.