How can I call a value in side the a function which is already evaluated.

1 vue (au cours des 30 derniers jours)
%% knt i calculated here.
nf=max(elem(:,4));
maxfl=max(elf(:,1));
for flno = 1:1:maxfl
for i=elf(1,1)
for j=1:1:nf
p=CGx(j)-CGx(i);
au=[1,0,0;0,1,p;0,0,1];
bu=(au)';
kse=eval(['KSE',num2str(flno),'l']);
k1=kse(1:nodof,1:nodof);
eval(['Ktts',num2str(flno),'l','=[k1,-k1*au;-bu*k1,bu*k1*au]']); %Transformed Stiffness matrix of each floor (6x6)
end
end
end
%% I have to call the knt inside the loop, how can i call please suggest me.
function [t,k_hat, R, keyp, key,Keyp,Key, delu, k_T, delF_hat, deludot, u0, udot0, uddot0] = NewmarkNon( t,Ug, delF, dt, u_t, u_c,F1, KGf, C, MGf, Rt, Rc, R, gamma, beta, key, k_T,u,udot,uddot)
knt=eval(['Ktts',num2str(n),'l']);
end
  29 commentaires
Stephen23
Stephen23 le 27 Sep 2022
"is there any way to proceed this operation without changing the code?"
No.
Chaudhary P Patel
Chaudhary P Patel le 27 Sep 2022
Thank you so much sir.

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Réponse acceptée

Bruno Luong
Bruno Luong le 27 Sep 2022
If you want to retrieve value of a variable from the parent workspace inside a function without passing it as argument onstead of normal eval do this
knt = evalin('caller','Ktts',num2str(n),'l'])
  8 commentaires
Chaudhary P Patel
Chaudhary P Patel le 27 Sep 2022
ok sir.
Thank you so much.
Walter Roberson
Walter Roberson le 27 Sep 2022
Postponing fixing your code by locking in using a hack like this is just going to result in it taking even longer to fix your code later.

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Plus de réponses (1)

Walter Roberson
Walter Roberson le 26 Sep 2022
It is not possible to do what you want to do using eval(). You will need to rewrite your code.
  2 commentaires
Walter Roberson
Walter Roberson le 26 Sep 2022
Do not store variables like KSE3l -- use a cell array like KSEl{n} instead. Or possibly a multidimensional array.
Likewise do not store into Ktts*l -- use a cell array like Kttsl{n} instead.
%% knt i calculated here.
nf=max(elem(:,4));
maxfl=max(elf(:,1));
for flno = 1:1:maxfl
for i=elf(1,1)
for j=1:1:nf
p=CGx(j)-CGx(i);
au=[1,0,0;0,1,p;0,0,1];
bu=(au)';
kse = KSEl{flno};
k1 = kse(1:nodof,1:nodof);
Kttsl{flno} = [k1,-k1*au;-bu*k1,bu*k1*au]']); %Transformed Stiffness matrix of each floor (6x6)
end
end
end
When you call your function (not shown in your code) pass in Kttsl as well.
%% I have to call the knt inside the loop, how can i call please suggest me.
function [t,k_hat, R, keyp, key,Keyp,Key, delu, k_T, delF_hat, deludot, u0, udot0, uddot0] = NewmarkNon( t,Ug, delF, dt, u_t, u_c,F1, KGf, C, MGf, Rt, Rc, R, gamma, beta, key, k_T, u, udot, uddot, Kttsl)
n = something appropriate
knt = Kttsl{n};
end
Walter Roberson
Walter Roberson le 26 Sep 2022
Please read http://www.mathworks.com/matlabcentral/answers/304528-tutorial-why-variables-should-not-be-named-dynamically-eval for information about why we strongly recommend against creating variable names dynamically.

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