Rounding towards zero or from zero

10 vues (au cours des 30 derniers jours)
Nick Austinos
Nick Austinos le 26 Sep 2022
Hi all; I want to round 3.6 to 3 but funny enough all the 'tozero' and 'fromzero' tiebreakers are returning the same answer i.e 4 which i dont want. How can this issue be fixed?
x=3.6
y=round(x,"TieBreaker","tozero")
z=round(x,"TieBreaker","fromzero")

Réponse acceptée

Les Beckham
Les Beckham le 26 Sep 2022
Modifié(e) : Les Beckham le 26 Sep 2022
There is no tie involved in rounding 3.6. If you wish, you can use floor instead:
floor(3.6)
ans = 3
If x was 3.5 instead, that would be a tie:
x = 3.5;
y=round(x,"TieBreaker","tozero")
y = 3
z=round(x,"TieBreaker","fromzero")
z = 4
  2 commentaires
Nick Austinos
Nick Austinos le 26 Sep 2022
I works thanks;
Les Beckham
Les Beckham le 26 Sep 2022
You are quite welcome.

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Plus de réponses (3)

Sam Chak
Sam Chak le 26 Sep 2022
Does this work for you?
x = 3.6;
y = floor(x)
y = 3

Steven Lord
Steven Lord le 26 Sep 2022
The tiebreaker methods only apply when the quantity to be rounded is halfway between the two numbers to which it could be rounded. So if you had 3.5 that's halfway between 3 and 4 and the tiebreaker would determine to which of those numbers 3.5 gets rounded.
round(3.5, 'TieBreaker', 'tozero')
ans = 3
round(3.5, 'TieBreaker', 'fromzero')
ans = 4
There's no tie to be broken if you're rounding 3.6.
There are other rounding functions that you may want to use instead of round. See their help or documentation pages for more information on each function's specific behavior.
[fix(3.6), floor(3.6), round(3.6), ceil(3.6)]
ans = 1×4
3 3 4 4

Image Analyst
Image Analyst le 26 Sep 2022
Try fix it rounds towards zero regardless if it's positive or negative, unlike floor which rounds towards negative infinity.
v = fix(3.6)
v = 3
v = fix(-9.4)
v = -9
v = floor(-9.4)
v = -10

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