Moving Decimal Places to the right

15 vues (au cours des 30 derniers jours)
Joydeb Saha
Joydeb Saha le 29 Sep 2022
Commenté : Jan le 29 Sep 2022
How can I get the number format as 1412701202.018284 for an exponent format data 1.412701202025964e+09. May be with sprintf "%.6f" or equivalent ? I need to do the task for a mat file I am attaching.
  2 commentaires
Jan
Jan le 29 Sep 2022
The number format matters for the text output only. In a comment above you mention, that you want to get a double as output. This is not meaningful. So which problem do you want to solve actually?
Rik
Rik le 29 Sep 2022
@Joydeb Saha You need to first respond to the question Jan raised: what is it you want? Do you want a char or a double as the output? In the first case you need sprintf, in the second case your question does not make sense, as that is just how the data is displayed, not the underlying data itself.
What exactly do you want to achieve?

Connectez-vous pour commenter.

Réponse acceptée

VBBV
VBBV le 29 Sep 2022
Modifié(e) : VBBV le 29 Sep 2022
format long % format long option
sprintf('%6f',1.412701202025964e+09)
ans = '1412701202.025964'
  9 commentaires
Joydeb Saha
Joydeb Saha le 29 Sep 2022
Déplacé(e) : Rik le 29 Sep 2022
VBBV, Attached the file which I want to be saved in the desired format I wrote
Jan
Jan le 29 Sep 2022
@Joydeb Saha: As said already, you can store the array in the shown format as CHAR array only:
S = sprintf('%6f\n', GTt)
If you want to store it numerically, the format has no meaning. Matlab stores value in the IEEE754 format and you cannot incfluence the location of the decimal point.

Connectez-vous pour commenter.

Plus de réponses (0)

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by