Running for loop on an equation
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Hi everyone,
I have the equation:
(1)
I have:
and
I have to compute for 0, 1, 2, ... 10.
I did it this way in MATLAB:
S = [1/2, 1/3, 1/2, 1/3, 1/3, 1/2;
1/2, 0, 0, 0, 0, 0;
0, 1/3, 1/2, 0, 0, 0;
0, 0, 0, 0, 1/3, 0;
0, 1/3, 0, 1/3, 0, 0;
0, 0, 0, 1/3, 1/3, 1/2];
u_0 = [0, 0, 1, 0, 0 ,0]';
for i = 0:10
u_k = S.*u_i;
I am stuck here. How can I write the equation (1) in matlab? Any help will be highly appreciated. Thanks alot in advance.
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Torsten
le 1 Oct 2022
Modifié(e) : Torsten
le 1 Oct 2022
S = [1/2, 1/3, 1/2, 1/3, 1/3, 1/2;
1/2, 0, 0, 0, 0, 0;
0, 1/3, 1/2, 0, 0, 0;
0, 0, 0, 0, 1/3, 0;
0, 1/3, 0, 1/3, 0, 0;
0, 0, 0, 1/3, 1/3, 1/2];
u_0 = [0, 0, 1, 0, 0 ,0]';
u = zeros(6,10);
u(:,1) = u_0;
for i = 2:11
u(:,i) = S*u(:,i-1);
end
u
%u./vecnorm(u)
%null(S-eye(6))
3 commentaires
Torsten
le 1 Oct 2022
To run it for 1,2,...,10, you must run the loop from 2 to 11. Think about it.
I corrected it above in my code.
Plus de réponses (1)
Davide Masiello
le 1 Oct 2022
Modifié(e) : Davide Masiello
le 1 Oct 2022
I suspect you want to do something like this
S = [ 1/2, 1/3, 1/2, 1/3, 1/3, 1/2;...
1/2, 0, 0, 0, 0, 0;...
0, 1/3, 1/2, 0, 0, 0;...
0, 0, 0, 0, 1/3, 0;...
0, 1/3, 0, 1/3, 0, 0;...
0, 0, 0, 1/3, 1/3, 1/2;...
];
u = zeros(6,11);
u(:,1) = [0, 0, 1, 0, 0 ,0]';
for col = 2:11
u(:,col) = S*u(:,col-1);
end
u
Beware of the fact that, to call , you must write
u(:,n+1)
This is because, unlike C, Matlab's indexing starts from 1 rather than 0.
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