Contour plot for a non rectangular object

70 vues (au cours des 30 derniers jours)
Ghazwan
Ghazwan le 5 Oct 2022
Commenté : William Rose le 6 Oct 2022
I have this case that I worked out in another software.
In the attached file, you can see the X,Y coordinates. The third column represents the results that I need to plot in a contour silimar to the one in the image above.
I tried several codes, but all of them plot on a rectagular area and/or not showing the same shape for the contour area. For example, the following code:
xyz = xlsread('data.xlsx');
x=xyz(2:end,1);
y=xyz(2:end,2);
z=xyz(2:end,3);
[X,Y]=meshgrid(min(x):max(x),min(y):max(y));
Z=griddata(x,y,z,X,Y);
contour(X,Y,Z)

Réponse acceptée

William Rose
William Rose le 5 Oct 2022
[X,Y]=meshgrid(x,y) makes a grid where all the x values are the same across the grid, and likewise for yhe y values.
You can fix it by making your own X and Y instead of using meshgrid.
Nx=41; Ny=9;
dx=1; dy=1; %adjust as desired
x=((0:Nx-1)-(Nx-1)/2)*dx; y=((0:Ny-1)-(Ny-1)/2)*dy;
[X,Y]=meshgrid(x,y); %initial approximation
Z1=X+2*Y;
subplot(211); surf(X,Y,Z1);
xlabel('X'); ylabel('Y'); axis equal; view(0,90)
%next: adjust the grid Y-values
Yadj=Y;
for i=1:Nx
if i<=5||i>=37
ymult=1;
elseif i>=32
ymult=(i-25)/12;
elseif i<=10
ymult=(17-i)/12;
else
ymult=0.5;
end
Yadj(:,i)=ymult*Y(:,i);
end
subplot(212); surf(X,Yadj,Z1);
xlabel('X'); ylabel('Yadj'); axis equal; view(0,90)
It works. The code to adjust the y-values is not very elegant, but it demonstrates the possibilities for creating a non-retangular grid.
  4 commentaires
Ghazwan
Ghazwan le 6 Oct 2022
Thank you, William. This is excellent.
Your code gave me a good idea of what to do next. After I generate the proper coordinate array, I will interpolate the original contour data into the new array. This way, I can ensure that the contour data will get appropriately mapped into the new coordinate points.
William Rose
William Rose le 6 Oct 2022
@Ghazwan, you are welcome. Your plan sounds good.

Connectez-vous pour commenter.

Plus de réponses (0)

Catégories

En savoir plus sur Line Plots dans Help Center et File Exchange

Produits


Version

R2019a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by