Cell contents assignment to a non-cell array object?

Hi there,

I have written this piece of code to store all the combination into a array of matrices.

for i=1:4,
 m = combnk(1:4,i)
 tester{i} = repmat(m,1)
end

When I tested it separately, it works fine. But when I combined it with other code in my project, the matlab gave me warning regarding tester{i} = repmat(m,1): Cell contents assignment to a non-cell array object

Anybody can enlighten me on this issue? Thanks a million in advance!

[Adam]

Is tester pre-declared or is it just created and resized in the loop?

[jessica xiang]

I have tested the other part of the code. No error. Just in case, I attached the full code here (but no excel sheet):

% Load demand excelfile
[num_demand,txt_demand,raw_demand] = xlsread('Testing_Demand.xlsx');

A = num_demand;
APrime = sum(A);
NumberOfElementsInBigMatrix = APrime(1,3);
tester = (round(NumberOfElementsInBigMatrix/2));
BigMatrix = cell(tester^2,(NumberOfElementsInBigMatrix-tester)^2);

% load supply excelfile
[num_incoming,txt_incoming,raw_incoming] = xlsread('Testing_Incoming.xlsx');
B = num_incoming;
[num_pivot,txt_pivot,raw_pivot] = xlsread('CoreToPartsPivot.xlsx');
C = num_pivot;
%convert demand core to part level
D = zeros(940,1); %matrix to store converted components
 for j=1:940,
    for i=1:27,
    %dont have 10R6700/reserve the last one as 10R6700; But components are not calculated
        if isnan(C(j,i)) 
        else   
            D(j,1)= D(j,1) + B(i,3)*C(j,i);
        end 
    end
 end

for i=1:4,
 m = combnk(1:4,i)
 tester{i} = repmat(m,1)
end 

for i=1:4,
 tester{i}
end

Answer 1

[Adam]

tester = (round(NumberOfElementsInBigMatrix/2));

will create tester as a double array. Then later on you try to assign to it as though it is a cell array in the for loop you provided at the top. If you created it as a double you cannot then assign to it with cell array syntax.

The initial code works standalone because tester was not previously declared as a double so it is created in the loop as a cell array.

[jessica xiang]

Omg! Yes! you are right! Thank you so much!