How to sort rows?
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>> A = [1 2; 4 3; 3 5; 2 1; 1 3; 4 5]
A =
1 2
4 3
3 5
2 1
1 3
4 5
>> B = sortrows(A)
B =
1 2
1 3
2 1
3 5
4 3
4 5
How to sort B, if entries of A are in java.math.BigInteger?
1 commentaire
Réponse acceptée
David Hill
le 12 Oct 2022
import java.math.*
%load sample BigInteger Array (100x2)
for k=1:100
J(k,:)=[BigInteger(repmat(num2str(randi(1e14,1)),1,3)),BigInteger(repmat(num2str(randi(1e14,1)),1,3))];
end
%have to do sort manually, any sort algorithm will work but need to use
%compareTo() for BigIntegers
c=0;
while c~=size(J,1)-1
c=0;
for k=1:size(J,1)-1
if J(k,1).compareTo(J(k+1,1))<1
c=c+1;
else
temp=J(k+1);
J(k+1)=J(k);
J(k)=temp;
end
end
end
3 commentaires
David Hill
le 13 Oct 2022
import java.math.*
%load sample BigInteger Array (100x2)
for k=1:100
J(k,:)=[BigInteger(repmat(num2str(randi(1e14,1)),1,3)),BigInteger(repmat(num2str(randi(1e14,1)),1,3))];
end
%have to do sort manually, any sort algorithm will work but need to use
%compareTo() for BigIntegers
c=0;
while c~=size(J,1)-1
c=0;
for k=1:size(J,1)-1
if J(k,1).compareTo(J(k+1,1))==0&&J(k,2).compareTo(J(k+1,2))==1
temp=J(k+1);
J(k+1)=J(k);
J(k)=temp;
elseif J(k,1).compareTo(J(k+1,1))<1
c=c+1;
else
temp=J(k+1);
J(k+1)=J(k);
J(k)=temp;
end
end
end
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