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Get total number of leap seconds relative to gps time

19 vues (au cours des 30 derniers jours)
user86753
user86753 le 13 Oct 2022
Modifié(e) : David Hill le 13 Oct 2022
I have a gps time stamp from a gps receiver, I'd like to convert that to GMT/UTC date and time.
GpsTime = 1667089162.11771
DayToSecs = 24*60*60;
TimeZero = datetime(1970,1,1, 'Format', 'd-MMM-y HH:mm:ss.SSS Z');
Tvec = GpsTime/DayToSecs + TdmsTimeZero;
Do I need to also adjust for leap seconds? If so, How do I return the total number of leap seconds from 'leapseconds' instead of the timetable?

Réponses (1)

David Hill
David Hill le 13 Oct 2022
Modifié(e) : David Hill le 13 Oct 2022
As long as the gps collection date is after 1 January 2017, then just subtract 18 seconds (37-19) see
Although your gps time seems to be in the future (not sure why).
GpsTime = 1667089162.11771;
utc=datetime(1980, 1, 6)+seconds(GpsTime-18);
utc=datetime(utc,'Format','yyyy-MM-dd HH:mm:ss.SSS')
utc = datetime
2032-11-03 00:19:04.117

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