definite complex integrals ..help me plz

6 vues (au cours des 30 derniers jours)
adrian zizo
adrian zizo le 14 Mar 2015
Commenté : Torsten le 18 Jan 2022
how ca I answer this integration by using matlab
(x^3+3)/((x^2+1)(x^2+4)) interval[-,] ?
I answer it by using calculation by using residue :
∴(z^2+1)(z^2+4)=(z-j)(z+j)+(z-j2)(z+j2)
z = +j
R_1=(-1+3)/((+j+j)(-1+4))=-1/3 j
z =j2
R_2=((-4)+3)/((-4+1)(j2+j2))=-1/12 j
I=-5/12 J(2πJ)=5/6 π

Réponses (1)

Roger Stafford
Roger Stafford le 14 Mar 2015
Your integral from minus infinity to plus infinity is divergent, because for large x the integrand behaves like 1/x, which would give log(x) as an integral, and log(x) becomes infinite. In other words, there is a non-zero residue at infinity and you are integrating through infinity, so the integral is not well-defined. It is as though you were integrating through a simple pole singularity on the finite complex plane, which would be ill-defined.
  2 commentaires
Matthew Young
Matthew Young le 18 Jan 2022
Obviously it's too late now but the integral is convegent.
you can split it into \int x^3 / ((x^2 +1)(x^2+4)) + \int 3 / ((x^2 +1)(x^2+4)). The first term evaluates to 0 and the second term behaves lke 1/x^4 . You can split the second term up using partial fractions and then use arctan to evaluate the integral.
Torsten
Torsten le 18 Jan 2022
This is only true if you mean the Cauchy Principal Value of the integral.
In the usual sense, the integral does not exist as @Roger Stafford noticed correcty.

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