Plotting discontinuous discrete signal with shift and fold

Hello !

I have a given question below

x[n]=   {1+n/3       -3<=n<=-1,

           1        0<=n<=3,
           0        other wise}
I have to plot this signal and I have developed the following code for that
      clc
  n=-10:1:10;
for i=1:length(n)

      if n(i)>=-3 && n(i)<=-1
      x(i)=1+(n(i)/3);
      elseif n(i)>=1 && n(i)<=3
          x(i)=1;
      else
          x(i)=0;
      end
  stem(x)
end
axis([-20 20 0 2])

but the resulting waveform is plotted for positive values of n, Kindly help me to plot the above sequence,

Answer 1

[Gnaneswar Nadh satapathi]

clc clear all close all n=-10:1:10; for i=1:length(n) if n(i)>=-3 && n(i)<=-1 x(i)=1+(n(i)/3); elseif n(i)>=1 && n(i)<=3 x(i)=1; else x(i)=0; end

end stem(n,x)

[Gnaneswar Nadh satapathi]

write stem outside rather than inside the loop

Answer 2

[Sk Group]

Signal Shift function in MATLAB

MATLAB CODE:

function [n1,x1] = sigshift(x,n,k)

n = 1:10;

k = 2;

x = exp(n);

if k>0

disp(‘Positive’);

n1 = n(1):n(end)+k;

x1 = [zeros(1,k) x];

else

disp(‘Negative’);

n1 = n(1)+k:n(end);

x1 = [x zeros(1,abs(k))]; % abs is for absolute value of (k) because quantity can never be (-ve) negative %

end

Signal Fold function in MATLAB

MATLAB CODE:

function [y n1] = sigfold(x,n)

n1 = -fliplr(n)

y = fliplr(x)

end

[Kunal]

discrete time signal folding code

Answer 3

[Kunal]

discrete time signal folding code

Answer 4

[Deepak]

how to folda given signal