parsing a vector by NaN into separte, unequal vectors into a cell array

I'm trying to parse a vector with NaN, into a cell array that is delineated by the start and stop of the NaN

example = [1 2 3 Na Na 2 3 Na 4 5 6 7 Na Na Na Na 1];

and turn that into

answer = {[1 2 3] [2 3] [4 5 6 7] [1]}

any suggestions? I've been using find(isnan(example)) to get the indices of NaN, but what I really need are the stop and stop indices of the non - NaN segments

Thanks!

Answer 1

[Sean de Wolski]

EDIT

Here's a fully vectorized engine that keeps original indices. This requires the Image Processing Toolbox.

x = [1 2 3 nan nan 2 3 nan 4 5 6 7 nan nan nan 1];

notnans = ~isnan(x);
idx = bwlabel(notnans);
n = histcounts(idx);
oneToN = 1:numel(x);
C = mat2cell([x(notnans); oneToN(notnans)],2,n(2:end))

[Matthew]

Thanks! Would there be a way to have the original indices in the answer?:

so that:

answer = {[1 2 3;1 2 3] [6 7; 2 3] [9 10 11 12; 4 5 6 7] [16;1];

Thanks for your help

[Sean de Wolski]

See EDIT

Answer 2

[Guillaume]

Here is a solution that does not require any toolbox:

x = [1 2 3 nan nan 2 3 nan 4 5 6 7 nan nan nan 1];

transitions = diff([1 isnan(x) 1]);
starts = find(transitions == -1);
lengths = find(transitions == 1) - starts;
nonanx = arrayfun(@(s, l) {[s:s+l-1; x(s:s+l-1)]}, starts, lengths)