I am beginner in matlab, and i struggly to resolve some exercice. can I have some advice according to this task?
1-1/3+1/5-1/7+1/9-..-1/1003

 Réponse acceptée

David Hill
David Hill le 29 Oct 2022

1 vote

n=1:502;
s=sum((-1).^(n+1)./(2*n-1))
s = 0.7849

7 commentaires

Alonso Mukendi Kalonji
Alonso Mukendi Kalonji le 29 Oct 2022
how did you get 502 for the loop
VBBV
VBBV le 29 Oct 2022
The highest term in the fraction of series is 1003. So it can obtained by this way 2*502-1
David Hill
David Hill le 29 Oct 2022
2*502 -1 = 1003 (last element). 2*n-1 is an expression for odd numbers.
Alonso Mukendi Kalonji
Alonso Mukendi Kalonji le 29 Oct 2022
This cod are not working
>> a = 1;
k = 502;
for x = 1:k
s = sum(((-1).^(x+1))./(2*(x-1)));
end
disp(s)
-9.9800e-04
No need for a loop. Just run the below code.
x=1:502;
s=sum((-1).^(x+1)./(2*x-1))
s = 0.7849
Maybe of interest:
syms n
s = simplify(symsum((-1)^n/(2*n+1),0,Inf))
s = 
Alonso Mukendi Kalonji
Alonso Mukendi Kalonji le 30 Oct 2022
I get it!
Thank you very much!

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