How to solve a function with uknown parameter with bisection method

y(x) = (x^3 + p^2x^2 - 10) sin (x) for x=13.61015 y= 13257 p= unknown 5.14<p<11.47

Answer 1

[David Hill]

x=13.61015;y=13257;
f=@(p)(x^3+p.^(2*x^2)-10)*sin(x)-y;
p=fzero(f,1)

p = 1.0259

P=1.01:.00001:1.03;
plot(P,f(P))%plot shows zero crossing cannot be between 5.14 and 11.47

Answer 2

[Torsten]

syms x y p
eqn = y - (x^3 + p^2*x^2 - 10)*sin(x) == 0;
eqn = subs(eqn,[x y],[13.61015,13257]);
p = vpasolve(eqn,p);
p = p(p>5.14 & p<11.47)

p = 

8.3215048459659113138901560210847

[Nikolas]

with bisception method

[Torsten]

At least you know now what the result of your bisection method should be :-)