size(libpointer.Value). Can it be done *without* copying the array

Hi,

I am returning a pointer to an array to MATLAB from a DLL using the following (simplified) code:

      arrayWidth = 16;
      wordsRequired = 16*2048*1024*16*16; %16GB of uint16's
      bufferPtr = lib.pointer('uint16Ptr'); %Null Pointer
      status = calllib('TestLib','GetBuffer',bufferPtr, wordsRequired);
      if (status >= 0)
          setdatatype(bufferPtr,'uint16Ptr',arrayWidth,wordsRequired/arrayWidth); %Set size
          wasSuccessful = 1;
      end

That all works fine, I get the pointer back and status from my library tells me that there was enough data in the buffer for the requested length.

Now, just to make sure, I did the following:

     size(bufferPtr.Value());

Expecting that to tell me the size - which it should as I used setdatatype. It tells me the correct values

ans =  16   536870912

Excellent.

BUT

What it also does, which I really don't want and have no idea why on earth it would do, is first make a local copy of the ENTIRE 16GB array. So it spends 30 seconds copying 16GB of RAM just to tell me two numbers which I told it on the line above.

Is there any way to get the size of a libpointer value without it copying it?

(p.s. I'm using 64bin Win7 with MATLAB 2013a)