Failure of initial objective function
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I am getting the dreaded "Failure in initial objective function evaluation. FMINCON cannot continue." Notification.
I am trying to use fmincon, but also using a simple loop within the function to see how parameters change over time.
Here is my code:
```
%Define Function- fmincon%
opts = optimset ('Display','iter','TolX',2e-9,'TolFun',2e-9,'MaxIter',100000,'MaxFunEvals',10000000,'FunValCheck','on');
[param,fval,exitflag,output,lambda,grad,hessian] = fmincon(@(param) Posterior(data,idx,param),param0,A,b,Aeq,beq,lb,ub,nonlcon,opts);
err = sqrt(diag(inv(hessian)));
%Run posterior function that is solved for Ep1.5%
k = 1; %number of predictors
function LL = Posterior(data,idx,param)
%n = 13; %number of obs: simple case
n = max(data.AgeMinus1); %Will update to go by ID
% define components of the function:
%EpPrior0 = param(idx.EpPrior);
Tau0 =param(idx.Tau); %Prior Variance/precision
Sigma_sq0 = param(idx.Sigma_sq); %Variance of
ShockInfo0 =param(idx.ShockInfo); % n = how informative the observation was
% Define vector to hold the shocks:
Shock = zeros(n, 1);
% Define a vector to hold the precision of the prior:
Tau = zeros(n+1,1);
Tau(1,:) = Tau0(1,:); % Variance of prior going into period 1
for i=1:n % Start the sampling
Shock(i,:) = data.Ep2(i,:) + (data.Ep2(i,:)- data.Ep1(i,:)).*(Sigma_sq0(i,:)./(ShockInfo0(i,:).*Tau(i,:))); %Ep 1.5
Tau(i+1,:) = ((Sigma_sq0(i,:)./ShockInfo0(i,:)).*Tau(i,:))./(Tau(i,:) + (Sigma_sq0(i,:)./ShockInfo0(i,:)));
end
LL = -sum(log(normpdf(Shock, 0, Sigma_sq0)));
end
```
How can I fix this error?
Thank you in advance!
6 commentaires
Chris
le 15 Nov 2022
Try calling
Posterior(data,idx,param0)
Do you get a valid answer?
Joshua Scott
le 15 Nov 2022
Matt J
le 15 Nov 2022
Try calling it within your script, before the optimization is launched.
Joshua Scott
le 15 Nov 2022
Torsten
le 15 Nov 2022
You should define "param0" in the same way as you extract the fitting parameters from "param" in "Posterior".
Joshua Scott
le 15 Nov 2022
Modifié(e) : Joshua Scott
le 15 Nov 2022
Réponses (1)
Then set some outputs in the function "Posterior" to see where the NaN operation occurs.
1 commentaire
Joshua Scott
le 16 Nov 2022
Déplacé(e) : Matt J
le 16 Nov 2022
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