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Can I use interpolation to small scale?

2 vues (au cours des 30 derniers jours)
승현 이
승현 이 le 5 Déc 2022
Commenté : 승현 이 le 5 Déc 2022
I usually use interp1 function to stratch data.
But now, i want shortening data and I'cant use interp1.
Results.Volume(:,1)= interp1(1:length(VOL),VOL,1:7200)';
=>length(VOL) = 8003
help me please!

Réponse acceptée

Askic V
Askic V le 5 Déc 2022
Modifié(e) : Askic V le 5 Déc 2022
Not really sure if I understood your question, but if you want less data points within the same interval, then just use interp1. Here is one example:
close all
x = linspace(0, 10, 100); % 100 points between 0 and 10
y = sin(x * 2);
plot(x,y)
hold on
% 2 times smaller in size
xi = linspace (0,10,50); % 50 points between 0 and 10
yi = interp1(x, y, xi, 'linear');
plot(xi,yi,'r')
  2 commentaires
승현 이
승현 이 le 5 Déc 2022
Déplacé(e) : Bruno Luong le 5 Déc 2022
I applogize my English!
I'd like to change the Y values for X of 1:8003 to the new Y2 for X2 of 1:7200.
If it works well,
plot(X2,Y2) will be overlapping plot(X,Y)
Thank you
승현 이
승현 이 le 5 Déc 2022
I solved problem using resample function.
Thank you for kind answer

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