Loop For extract maximum rows of matrix based on vectors
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Afficher commentaires plus anciens
abdullah al-dulaimi
le 7 Déc 2022
Réponse apportée : Fangjun Jiang
le 7 Déc 2022
I have this data , Consist of 3 vectors, i want to create a Loop for 1:5: size(data) , to extract rows that have maximum value for vector 2 (colomn number 2)
1 3 4
1 5 4
1 6 4
1 2 4
1 1 4
2 4 4
2 4 4
2 4 4
2 4 4
2 5 4
1 1 4
1 1 4
1 2 4
1 3 4
1 5 4
2 5 4
2 5 4
2 5 4
2 5 4
2 6 4
The result will be
1 6 4
2 5 4
1 5 4
2 6 4
1 commentaire
Walter Roberson
le 7 Déc 2022
Is the rule that you want to find the maximum for each group of lines that has the same value in the first column? Even if the third column is different? Or should it be groups of lines that have the same first and third column ?
Réponse acceptée
Voss
le 7 Déc 2022
data = [
1 3 4
1 5 4
1 6 4
1 2 4
1 1 4
2 4 4
2 4 4
2 4 4
2 4 4
2 5 4
1 1 4
1 1 4
1 2 4
1 3 4
1 5 4
2 5 4
2 5 4
2 5 4
2 5 4
2 6 4
];
[n_rows,n_cols] = size(data);
assert(mod(n_rows,5) == 0)
result = zeros(n_rows/5,n_cols);
for ii = 1:5:n_rows-4
temp_data = data(ii+(0:4),:);
[~,idx] = max(temp_data(:,2));
result((ii-1)/5+1,:) = temp_data(idx,:);
end
disp(result);
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Plus de réponses (1)
Fangjun Jiang
le 7 Déc 2022
a=[1 3 4
1 5 4
1 6 4
1 2 4
1 1 4
2 4 4
2 4 4
2 4 4
2 4 4
2 5 4
1 1 4
1 1 4
1 2 4
1 3 4
1 5 4
2 5 4
2 5 4
2 5 4
2 5 4
2 6 4];
b=reshape(a',3,5,[])
c=transpose(squeeze(max(b,[],2)))
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