textscan different number of floating digits
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Hello Matlab Community,
I have a dataset with 'Loggers_3340_837584_20.5m_TXT' format.
For example:
'Loggers_3340_838653_20.55m_TXT
'Loggers_3340_200584_30.0m_TXT
'Loggers_3340_636400_23.5m_TXT
'Loggers_3340_268584_12.5m_TXT
Bold parts are changing in each file.
I am using below script to read files in loop. My problem is changing decimal digits in depth (xx.xm or xx.xxm) . I put only the reading part of the script to get your opinions.
If I use '%g\n', the files ending with one digit zero are read as 30m instead of 30.0m.
But if I use '%0.1f' or '%0.2f', the output is whether two or one decimal digits which does not work in my case.
DOm{iii}=readloggerstxt(['Loggers_','3340','-',num2str(idm3(iii),'%6d'),'_',num2str(idm4(iii),'%g\n'),'m.TXT'])
What can be an alternative way to read varying decimal parts?
Thank you in advance!
1 commentaire
Stephen23
le 20 Déc 2022
Modifié(e) : Stephen23
le 20 Déc 2022
You should use READTABLE() to get the correct variable types, e.g.:
fnm = 'Loggers_3340-106208_33.7m.txt';
obj = detectImportOptions(fnm, 'filetype','text', 'delimiter',',', ...
'VariableNamingRule','preserve', 'VariableNamesLine',8, 'VariableUnitsLine',9);
obj = setvartype(obj, 'Unix Timestamp','uint64');
tbl = readtable(fnm, obj)
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Stephen23
le 20 Déc 2022
Modifié(e) : Stephen23
le 20 Déc 2022
"...but I need to order them according to the last part which is 30.0m 31.65m 33.5m"
So why not just sort the filenames? That is very easy to do:
P = '.'; % absolute or relative path to where the files are
S = dir(fullfile(P,'Loggers*.txt'));
{S.name} % wrong order
C = regexp({S.name},'\d+\.?\d*(?=m)','once','match')
[~,X] = sort(str2double(C));
S = S(X);
{S.name} % right order
Plus de réponses (1)
Image Analyst
le 20 Déc 2022
Modifié(e) : Image Analyst
le 20 Déc 2022
Did you try using dir?
fileList = dir('Loggers*.txt');
allFileNames = {fileList.name}; % Get all filenames into a cell array.
for iii = 1 : numel(allFileNames)
% Read results into the two arrays.
DOm{iii} = readloggerstxt(allFileNames{iii});
readloggerstxtDOm{iii} = readloggerstxt(allFileNames{iii});
% Now, here comes the calculations
end
6 commentaires
Image Analyst
le 20 Déc 2022
OK, good. I always think it's easier to read if you use sprintf() to construct the filename instead of the bracket and num2str way.
With both the way you made the filename, and the way I did, both ways sent a string into readloggerstxt() so if it's not working, you'll have to figure out why readloggerstxt() does not like a string.
And glad you finally understand what I was saying about the double = giving a syntax error.
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