Generate random short fiber in matlab?
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Kindly look into the below code, i am not able to run it, if there is any issue.
function Fiber=Generate_Fiber(x,y,z,L,N)
%input
%x=[x1 x2]: x boundaries of the box
%y=[y1 y2]: y boundaries of the box
%z=[z1 z2]: z boundaries of the box
%L: Length of fibers
%N: Number of fibers
%output
%Fiber: (N,6) matrix of fiber coordinates with (:,1), (:,2) and (:,3) are x,y, and z coordinates of one end
%and (:,4),(:,5) and (:,6) are x,y, and z coordinates of the other end.
for i=1:1:N
while 1
x1=min(x)+(max(x)-min(x))*rand(1);
y1=min(y)+(max(y)-min(y))*rand(1);
z1=min(z)+(max(z)-min(z))*rand(1);
theta=2*pi*rand(1);
v=2*rand(1)-1;
x2=x1+L*sqrt(1-v^2)*cos(theta);
y2=y1+L*sqrt(1-v^2)*sin(theta);
z2=z1+L*v;
if x2<=x(2) && x2>=x(1) && y2<=y(2) && y2>=y(1) && z2<=z(2) && z2>=z(1)
break;
end
end
Fiber(i,1)=x1;
Fiber(i,2)=y1;
Fiber(i,3)=z1;
Fiber(i,4)=x2;
Fiber(i,5)=y2;
Fiber(i,6)=z2;
end
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Dongyue
le 13 Jan 2023
Please try this
result = Generate_Fiber([0,1],[0,1],[0,1],0.5,2)
function Fiber=Generate_Fiber(x,y,z,L,N)
%input
%x=[x1 x2]: x boundaries of the box
%y=[y1 y2]: y boundaries of the box
%z=[z1 z2]: z boundaries of the box
%L: Length of fibers
%N: Number of fibers
%output
%Fiber: (N,6) matrix of fiber coordinates with (:,1), (:,2) and (:,3) are x,y, and z coordinates of one end
%and (:,4),(:,5) and (:,6) are x,y, and z coordinates of the other end.
Fiber = zeros(N,6);
for i=1:1:N
while 1
x1=min(x)+(max(x)-min(x))*rand(1);
y1=min(y)+(max(y)-min(y))*rand(1);
z1=min(z)+(max(z)-min(z))*rand(1);
theta=2*pi*rand(1);
v=2*rand(1)-1;
x2=x1+L*sqrt(1-v^2)*cos(theta);
y2=y1+L*sqrt(1-v^2)*sin(theta);
z2=z1+L*v;
if x2<=x(2) && x2>=x(1) && y2<=y(2) && y2>=y(1) && z2<=z(2) && z2>=z(1)
break;
end
end
Fiber(i,1)=x1;
Fiber(i,2)=y1;
Fiber(i,3)=z1;
Fiber(i,4)=x2;
Fiber(i,5)=y2;
Fiber(i,6)=z2;
end
end
5 commentaires
Rik
le 16 Jan 2023
If you have trouble with Matlab basics you may consider doing the Onramp tutorial (which is provided for free by Mathworks).
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