How do I print a legend using a character array and integer array?

I want to print a legend that looks like this:

1st entry: 'Current solution, 4800 m DR'

2nd entry: 'Current solution, 7000 m DR'

3rd entry: 'Current solution, 9000 m DR'

4th entry: 'Archive solution, 4800 m DR'

5th entry: 'Archive solution, 7000 m DR'

6th entry: 'Archive solution, 9000 m DR'

The numbers come from a structure array. I'm trying to use sprintf, but I'm having troubles with the format of the 'Current' and 'Archive' strings. A character array does not work since sprintf iterates through each character instead of each word. Do I need to do a cell array and then do a comma separated list for that?

[Walter Roberson]

A character array does not work since sprintf iterates through each character instead of each word.

A = 'Current'

A = 'Current'

sprintf('->%s<-', A)

ans = '->Current<-'

sprintf('->%c<-', A)

ans = '->C<-->u<-->r<-->r<-->e<-->n<-->t<-'

You were using the wrong format item.

Answer 1

[Stephen23]

COMPOSE() is perfect for this, but was first introduced in R2016b. You could use ARRAYFUN() or CELLFUN():

C = {'Current','Current','Current','Archive','Archive','Archive'};
V = [4800,7000,9000,4800,7000,9000];
fnh = @(t,n)sprintf('%s solution, %d m DR',t,n);
lgd = cellfun(fnh,C(:),num2cell(V(:)), 'uni',0)

lgd = 6×1 cell array
    {'Current solution, 4800 m DR'}
    {'Current solution, 7000 m DR'}
    {'Current solution, 9000 m DR'}
    {'Archive solution, 4800 m DR'}
    {'Archive solution, 7000 m DR'}
    {'Archive solution, 9000 m DR'}

Answer 2

[Fangjun Jiang]

a="current";
b={'archive'};
c='current';
sprintf('%s',a)

ans = 'current'

sprintf('%s',b{1})

ans = 'archive'

sprintf('%s',c)

ans = 'current'

[Shelley Snider]

I'm looking for something that prints the list of entries in my question.

[Fangjun Jiang]

Use a for-loop, or use the cellfun() that @Stephen23 demonstrated.

Another trick is below, if you put the data in the right format

data={'1st','2nd','3rd';'Current','Archive','Current';4800,7000,9000};
sprintf('%s entry: ''%s solution, %d m DR''\n',data{:})

ans = 
    '1st entry: 'Current solution, 4800 m DR'
     2nd entry: 'Archive solution, 7000 m DR'
     3rd entry: 'Current solution, 9000 m DR'
     '