I am trying to write the equation of the graph and plot it.
So far I have written this equation, however when I plot it, there is a point at (-3,-3) and I am not sure why. I need to plot it as a continuous time signal.
n = -6:6;
x = @(n) n.*((n>-4)&(n<=-2))+4*(n==-2)+(-2)*(n==2)+0*(n==4);
plot(n,x(n));

1 commentaire

Adam Danz
Adam Danz le 20 Jan 2023
@collegestudent I edited your question to run your code so that it produces the plot.

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 Réponse acceptée

x = @(t) (t+4).*(t>-4 & t<-2) + (t-4).*(t>2 & t<4);
t = -6:0.01:6;
plot(t,x(t))
grid on

2 commentaires

Do you know why when I try to evaluate the equation of x(t) = 2x(t-2) I get the error of "Operator '*' is not supported for operands of type 'function_handle'."
x2 = (2*x)*(t-2);
x2 = 2*x(t-2)
instead of
x2 = (2*x)*(t-2);
x(t-2) stands for: evaluate function x at t-2, not for: multiply x by t-2.

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