How can I put variable equal to zero in loop

in this code
w= input('k=');
for k=1:w
m=sym('U1',[1 k])
end
I need to put U1k in every iteration =0
U11=0
U12=0
U13=0 .......

1 commentaire

Adham Ahmed
Adham Ahmed le 8 Fév 2023
thank you
I need for k=1
U11=0
for k=2
U12=0
for k=3
U13=0
an so on.........
for k=9
U19=0
using loop

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Réponses (3)

Dinesh
Dinesh le 8 Fév 2023
Hi Adham Ahmed,
For any input 'w', to create that many number of variables during run time, 'sprintf' function can be used.
Then the 'eval' function can be used to initialize them to zero as you wanted to do.
The following code takes an input 'w' and then creates that many number of variables namely U11, U12, ...., U1w at run time and initializes all of them to zero.
w = input('k='); % takes an input 'w'
for k = 1:w
var_name = sprintf('U%d%d', 1, k); % creates the dynamic variable name
eval([var_name '= 0;']); % initialization to zero
end
In the above code, for an example, if the input 'w' is 3, then you can print 'U13' using
disp(U13);
to confirm the variable creation and value assignment.

2 commentaires

Steven Lord
Steven Lord le 8 Fév 2023
Can you dynamically create variables with numbered names like U11, U12, U13, etc.? Yes.
Should you do this? The general consensus is no. That Answers post explains why this is generally discouraged and offers several alternative approaches.
Adham Ahmed
Adham Ahmed le 8 Fév 2023
thank you
I need for k=1
U11=0
for k=2
U12=0
for k=3
U13=0
an so on.........
for k=9
U19=0
using loop

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% using loop
w= 10; %input('k=');
for k=1:w
m=sym('U1',[1 k]) == 0;
end
m
m = 
you can also do so without using loop
% without loop
m=sym('U1',[1 w]) == 0
m = 

2 commentaires

Adham Ahmed
Adham Ahmed le 8 Fév 2023
thank you
but only the last one to be zero
Adham Ahmed
Adham Ahmed le 8 Fév 2023
thank you
I need for k=1
U11=0
for k=2
U12=0
for k=3
U13=0
an so on.........
for k=9
U19=0
using loop

Connectez-vous pour commenter.

Shubham
Shubham le 8 Fév 2023
Here's a code that sets the symbol 'U1k' to zero in each iteration:
w = input('k=');
for k = 1:w
eval(sprintf('U1%d=0', k))
end

1 commentaire

Adham Ahmed
Adham Ahmed le 8 Fév 2023
thank you
I need for k=1
U11=0
for k=2
U12=0
for k=3
U13=0
an so on.........
for k=9
U19=0
using loop

Connectez-vous pour commenter.

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