Forward differencing, error when plotting u(x_i)!

5 vues (au cours des 30 derniers jours)
Andrew Sanderson
Andrew Sanderson le 23 Oct 2011
Guys,
I know this must be a reallllly trivial error, but I seriously cannot see what is going on. I am purely plotting 100 elements against another 100 elements and I am getting the following error:
??? Subscript indices must either be real positive integers or logicals.
Error in ==> Test at 22 plot(x,u);
The code I am using is below (would really appreciate some help in this because it's driving me crazy; usually i am good at debugging!):
function Test(n,f,length_check,plot)
% Create grid:
x_min = 1;
x_max = 11;
dx = (x_max - x_min)/(n-1);
x(1) = x_min;
for i = 1:(n-1);
x(i+1) = x(i) + dx;
end
x(n) = [];
% Compute u(x):
i = 1:(n-1);
u(i)= f(x(i));
if (length(x)==length(u));
'Vector lengths agree'
end
%figure;
length(x)
length(u)
plot(x,u);
axis([0,12,-0.1,0.4]);
xlabel('x'); ylabel('u');
grid on;
CHEERS FOR THE HELP GUYS!
Andrew.
  2 commentaires
the cyclist
the cyclist le 23 Oct 2011
It would be helpful if you used the "Code" button to format your code into a more readable form.
the cyclist
the cyclist le 23 Oct 2011
Also, it looks like you haven't defined "n" or the function "f" for us, so I don't think we can run your code to look for errors.

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Réponse acceptée

Jan
Jan le 23 Oct 2011
??? Subscript indices must either be real positive integers or logicals.
Error in ==> Test at 22 plot(x,u);
The you have defined a variable called "plot". You can check this by using the debugger:
dbstop if error
Then start your program until it stops at the error. Now user this to check the type of "plot":
which plot
whos plot
Solution: Do not use names of builtin functions for variables.
  2 commentaires
Andrew Sanderson
Andrew Sanderson le 23 Oct 2011
OH! Of course... Thanks so much for this help. And for the other guys; sorry for the unreadable code, this was my first ever post on the matlab forums :)
Jan
Jan le 23 Oct 2011
You do not have to apologize. Simple edit the original question, mark the code and press the "{} code" button. I've done this for you this time.

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Plus de réponses (1)

Andrew Sanderson
Andrew Sanderson le 23 Oct 2011
function Development_Task_1(n,f,length_check,plot_check)
% Create grid:
x_min = 1;
x_max = 11;
dx = (x_max - x_min)/(n-1);
x(1) = x_min;
for i = 1:(n-1);
x(i+1) = x(i) + dx;
end
x(n) = [];
% Compute u(x):
i = 1:(n-1);
u(i)= f(x(i));
if (length(x)==length(u));
'Vector lengths agree'
end
%figure;
length(x)
length(u)
plot(x,u);
axis([0,12,-0.1,0.4]);
xlabel('x'); ylabel('u');
grid on;
% We must compute:
%
% du u(i+1) - u(i)
% -- = -------------
% dx dx
%
% Using the method of forward differencing;
i = 2 : (n-1);
dudx(i) = (u(i) - u(i-1)) / dx;
dudx(n-1) = [];
figure;
plot(x,dudx);
if (plot_check == 1)
if (length_check == 1)
fig_ = figure;
lengths_ = [length(x), length(u), length(dudx)];
names_ = {'x','u(x)','u''(x)'};
uitable(fig_, 'Data', lengths_, 'ColumnName', names_);
end
end
Sorry after changing the input to plot_check I am still getting the same error.
The inputs I have been using are;
n = 100; f = @(x) exp(-x);
Thanks,
Andrew.
  1 commentaire
Andrew Sanderson
Andrew Sanderson le 23 Oct 2011
EDIT: Sorry, I am having an absolute nightmare with matlab today. The above answer did work, apologies for the stupidity and cheers for all the help!

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