Toggle between temperature units for unit conversion
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Hi,
I am trying to make a simple temeprature unit conversion app in MATLAB app maker with a dropdown menu to toggle between temperature units: C, F, and K. I used switch case function to convert degree c to F or K; however, when I want to return back to c or toggle between the units the program gives wrong values. Please help me complete the code to be able to toggle between temperature units. Thanks
function DropDownValueChanged(app, event)
Value=app.TemperatureEditField.Value
switch app.DropDown.Value
case 'C'
app.TemperatureEditField.Value=Value;
case 'F'
app.TemperatureEditField.Value=Value*1.8+32;
case 'K'
app.TemperatureEditField.Value=Value+273.15;
end
end
1 commentaire
Fangjun Jiang
le 14 Fév 2023
Of course it has issues. If you continue selecting "K", the program flow will continu adding 273.15 to the current value. You need to add something to recognize the current unit.
Réponse acceptée
Voss
le 17 Fév 2023
You need to take into account what the old unit was before it was changed. Fortunately, the ValueChangedFcn of a uidropdown provides an event structure which contains that information. See the attached app.
2 commentaires
Jon
le 17 Fév 2023
Very nice!
Gives the OP what he wanted with an interface with just one box. Good to know that the event structure returns the previous value.
Plus de réponses (1)
Jon
le 14 Fév 2023
Modifié(e) : Jon
le 14 Fév 2023
I think this does what you want.
I have fixed a few errors in your original code, I think you were confused about the value of the drop down selection and the value of the temperature, which was in the edit field.
Also I added another edit field for the resulting output in the new units. Otherwise, as mentioned by @Fangjun Jiang, with repeated operation the value stored in the original edit field no longer has units of C, so the conversion which you have which convert from C to F or K would no longer be correct. Easier to keep the original value as is and then just output to a different edit field.
11 commentaires
Image Analyst
le 23 Fév 2023
Not sure what you mean. Isn't it the obvious:
Tc = (Tf - 32) * 5/9;
Rho_H2O = 999.6 + 2.0438e-1 * Tc - 6.174e-2 * Tc ^ 1.5
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