Effacer les filtres
Effacer les filtres

Error msg in fminbnd

2 vues (au cours des 30 derniers jours)
nirwana le 16 Mar 2023
Commenté : nirwana le 16 Mar 2023
Hi all
I an trying to find minimum value of function using fminbnd sing this script
x=linspace (0,6);
plot (y);
Error using fcnchk
FUN must be a function, a valid character vector expression, or an inline function object.

Error in fminbnd (line 198)
funfcn = fcnchk(funfcn,length(varargin));
But it give me an error mgs as shown, i don't understand what part in my code that have mistake.

Réponse acceptée

AL le 16 Mar 2023
fun = @(x) 6*cos(x) + 1.5*sin(x); % Define the function
x_min = fminbnd(fun, 0, 6); % Find the minimum within the interval [0,6]
y_min = fun(x_min); % Evaluate the function at the minimum x value
plot(linspace(0,6), fun(linspace(0,6))); % Plot the function
hold on
plot(x_min, y_min, 'ro'); % Mark the minimum point on the plot
hold off
disp(['The minimum value of y is ', num2str(y_min), ' at x = ', num2str(x_min)]);
Try this Once.
  3 commentaires
John D'Errico
John D'Errico le 16 Mar 2023
fminbnd solves for the minimum of a FUNCTION. When you define x as a vector, then create y, as a VECTOR, y is just a list of numbers. It is not a function anymore, so fminbnd must fail.
What @AL did was create fun as a function. And now it works.
nirwana le 16 Mar 2023
Thanks a lot @John D'Errico. Now I understand

Connectez-vous pour commenter.

Plus de réponses (0)


En savoir plus sur Loops and Conditional Statements dans Help Center et File Exchange


Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by