how to find nearest distant points for two unequal sized pair of data

I have two set of points set1>>{A1(6840*1),B1(6840*1)} and set2>>{A2(10227*1),B2(10227*1)}. I want to find the nearest distant points(<=0.05) taking one set fixed. I have tried like this

for i=1:length(A2); difference1=A1-A2(i); difference2=B1-B2(i); P=sqrt((difference1.^2)+(difference2.^2))<=0.05; end A3=A2(P); B3=B2(P); so the nearest points w.r.t set (A1,B1) is (A3,B3) but this result is not matching with manual result.please help

[Ortinomax]

Please use the button "code", it makes your writing easy to read.

Answer 1

[Ortinomax]

When you do

A3=A2(P); B3=B2(P);

P is a "boolean", it is either at 0 or 1 depending of the inequality. I tried this, and it seems to work. For each poitn of [A1;B1], it gives the nearest [A2;B2] points (and C3 indicates i we respect the proximity limit).

C3=0*A1;

for k=1:length(A1); 

      C=A2-A1(k)+1i*(B2-B1(k))
      [minD ind]=min(abs(C))
      A3(k)=A2(ind);
      B3(k)=B2(ind);
      C3(k)=minD<=0.05
  end

[LUI PAUL]

thanks Ortino...its working... i have changed the size..will it be ok? A3=(A3)'; B3=(B3)';