Effacer les filtres
Effacer les filtres

How to solve "system contains a nonlinear equation"

9 vues (au cours des 30 derniers jours)
Fatemeh
Fatemeh le 7 Mai 2023
Commenté : Fatemeh le 7 Mai 2023
Hello, when I run the code below, I get an error because the square of the second derivative of y(x) is used. Could someone please tell me how I can solve this type of problem?
syms y(x) x Y
mum=2;
r=0.05;
m=0.01;
p=1;
s=1;
t=0.1;
a=0.25;
b=0.25;
l=0.5;
t0= ((1/(r+p*s-m))^(1/(1-a-b)))+((1/(r+p*s-m))^(1/(1-a-b)))*((1/(r+t*p*s-m))^(1/(1-l)));
Dy = diff(y);
D2y = diff(y,2);
mo=1/(r-((p*Dy*x*s*mum)/y)-((Dy*x*mum)/y)+((Dy*x*mum*m)/y)-((Dy*x*(s^2)*(mum^2))/y)-((D2y*(x^2)*(s^2)*(mum^2))/(2*y)));
mi=1/(r-((t*p*Dy*x*s*mum)/y)-((Dy*x*mum)/y)+((Dy*x*mum*m)/y)-((Dy*x*(s^2)*(mum^2))/y)-((D2y*(x^2)*(s^2)*(mum^2))/(2*y)));
ode = y-(1/x)*(mo^(1/(1-a-b))+mo^(1/(1-a-b))* mi^(1/(1-l)));
[VF,Subs] = odeToVectorField(ode);
Error using mupadengine/feval_internal
System contains a nonlinear equation in 'diff(y(x), x, x)'. The system must be quasi-linear: highest derivatives must enter the differential equations linearly.

Error in odeToVectorField>mupadOdeToVectorField (line 171)
T = feval_internal(symengine,'symobj::odeToVectorField',sys,x,stringInput);

Error in odeToVectorField (line 119)
sol = mupadOdeToVectorField(varargin);
odefcn = matlabFunction(VF, 'Vars',{x,Y});
bcfcn = @(ya,yb)[ya(1)-t0;yb(1)];
xmesh = linspace(1,80,150);
solinit = bvpinit(xmesh, [0 0]);
sol = bvp4c(odefcn,bcfcn,solinit);
plot(sol.x,sol.y(1,:))

Réponses (1)

Walter Roberson
Walter Roberson le 7 Mai 2023
Modifié(e) : Walter Roberson le 7 Mai 2023
syms y(x) x Y
mum=2;
r=0.05;
m=0.01;
p=1;
s=1;
t=0.1;
a=0.25;
b=0.25;
l=0.5;
t0= ((1/(r+p*s-m))^(1/(1-a-b)))+((1/(r+p*s-m))^(1/(1-a-b)))*((1/(r+t*p*s-m))^(1/(1-l)));
Dy = diff(y);
D2y = diff(y,2);
mo=1/(r-((p*Dy*x*s*mum)/y)-((Dy*x*mum)/y)+((Dy*x*mum*m)/y)-((Dy*x*(s^2)*(mum^2))/y)-((D2y*(x^2)*(s^2)*(mum^2))/(2*y)));
mi=1/(r-((t*p*Dy*x*s*mum)/y)-((Dy*x*mum)/y)+((Dy*x*mum*m)/y)-((Dy*x*(s^2)*(mum^2))/y)-((D2y*(x^2)*(s^2)*(mum^2))/(2*y)));
ode = y-(1/x)*(mo^(1/(1-a-b))+mo^(1/(1-a-b))* mi^(1/(1-l)));
ode
ode(x) = 
The denominator has d^2y/dx^2 in it, and that term is squared, so the square of d^2y/dx^2 appears in the equation.
sode = simplify(expand(ode(x)), 'steps', 50)
sode = 
If you look at which is d^2y/dx^2 you can see that it appears to the 4th power in the expanded version, so the situation might be even worse than it seems at first.
  6 commentaires
Torsten
Torsten le 7 Mai 2023
Modifié(e) : Torsten le 7 Mai 2023
Then try it out:
syms y Dy D2y x Y
mum=2;
r=0.05;
m=0.01;
p=1;
s=1;
t=0.1;
a=0.25;
b=0.25;
l=0.5;
t0= ((1/(r+p*s-m))^(1/(1-a-b)))+((1/(r+p*s-m))^(1/(1-a-b)))*((1/(r+t*p*s-m))^(1/(1-l)));
mo=1/(r-((p*Dy*x*s*mum)/y)-((Dy*x*mum)/y)+((Dy*x*mum*m)/y)-((Dy*x*(s^2)*(mum^2))/y)-((D2y*(x^2)*(s^2)*(mum^2))/(2*y)));
mi=1/(r-((t*p*Dy*x*s*mum)/y)-((Dy*x*mum)/y)+((Dy*x*mum*m)/y)-((Dy*x*(s^2)*(mum^2))/y)-((D2y*(x^2)*(s^2)*(mum^2))/(2*y)));
ode = y-(1/x)*(mo^(1/(1-a-b))+ mi^(1/(1-l)))
ode = 
D2ynum = solve(ode==0,D2y);
D2ynum = D2ynum(2);
f = matlabFunction(D2ynum,"Vars",{x, [y Dy]});
odefcn = @(x,y)[y(2);f(x,[y(1),y(2)])];
bcfcn = @(ya,yb)[ya(1)-t0;yb(1)];
xmesh = linspace(1,80,150);
solinit = bvpinit(xmesh, [1 1]);
sol = bvp4c(odefcn,bcfcn,solinit);
plot(sol.x,sol.y)
Fatemeh
Fatemeh le 7 Mai 2023
Thanks much @Torsten

Connectez-vous pour commenter.

Catégories

En savoir plus sur Function Creation dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by