# Removing rows except containing certain numbers of "33"

2 vues (au cours des 30 derniers jours)
Smithy le 26 Mai 2023
Commenté : Stephen23 le 1 Juin 2023
Hello everybody,
I hope to keep the row with the containing certain numbers of "33" of the last two digits in 1st column of result.
and I hope to remove other rows.
the expecting answer is [133 1133; 2, 4] in this case. ()
I tried with
result(~ismember(result(:,1),'33'), :) = []; % It does not work.
result(~contains(string(result(:,1)),"33"), :) = []; % 332 also is included in result variable.
but it doest not work. 332 also is included in result variable.
Is there a way to check wheter last two digits meet the condition?
x = [103 133 1133 1344 332 105 1105 15 53 511]';
y = [1 2 4 5 7 2 1 8 10 1]';
result = [x,y];
% How to remove the rows except containing certain numbers of 1st column of result
% if I would like to keep the row with the "33" of the last two digits in 1st column of result,
% 133 and 1133 accept the condition. and 332 does not meet the condition.
% so the expecting result will be [133 2; 1133, 4]
result(~ismember(result(:,1),'33'), :) = []; % It does not work.
result(~contains(string(result(:,1)),"33"), :) = []; % 332 also is included in result variable.
##### 1 commentaireAfficher -1 commentaires plus anciensMasquer -1 commentaires plus anciens
Stephen23 le 26 Mai 2023
As Dyuman Joshi correctly wrote, mixing up text and numeric data will not help you.
Just stick to the numeric domain and use MOD or REM.

Connectez-vous pour commenter.

### Réponse acceptée

Hiro Yoshino le 26 Mai 2023
You should use "pattern" to detect what you want in the strings as follows:
x = [103 133 1133 1344 332 105 1105 15 53 511]';
y = [1 2 4 5 7 2 1 8 10 1]';
result = [x,y]
result = 10×2
103 1 133 2 1133 4 1344 5 332 7 105 2 1105 1 15 8 53 10 511 1
Define pattern
pat = "33";
TF = endsWith(string(result(:,1)),pat);
Extract what I want
result(TF,:)
ans = 2×2
133 2 1133 4
Does this fit what you want to achieve?
##### 1 commentaireAfficher -1 commentaires plus anciensMasquer -1 commentaires plus anciens
Smithy le 26 Mai 2023
Thank you very much for your huge helps. I really really appreciate with it. It works really well for me.

Connectez-vous pour commenter.

### Plus de réponses (1)

Dyuman Joshi le 26 Mai 2023
You are trying to compare numeric data with character data. You will have to convert your initial data to do that comparison.
Instead, just use rem() or mod()
x = [103 133 1133 1344 332 105 1105 15 53 511]';
y = [1 2 4 5 7 2 1 8 10 1]';
%Checking condition - last two digits correspond to 33
idx = rem(x,100)==33;
%Values corresponding to the condition
result = [x(idx)';y(idx)']
result = 2×2
133 1133 2 4
##### 1 commentaireAfficher -1 commentaires plus anciensMasquer -1 commentaires plus anciens
Stephen23 le 1 Juin 2023
+1 simpler and more efficient without the superfluous type conversions.

Connectez-vous pour commenter.

### Catégories

En savoir plus sur Numeric Types dans Help Center et File Exchange

R2023a

### Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by