Single iteration with lsqnonlin (or fsolve), only compute new X0
2 vues (au cours des 30 derniers jours)
I want lsqnonlin (or fsolve) to only carry out one iteration, ie. compute the new X, and then stop. No further function evaluations.
So ideally I dont even want it to compute the new values of the objective function, but I definitely do not want extra function evaluations for the jacobian or first order optimality conditions at the new guess for X.
(My question is similar to an earlier question by me:
... but now function evaluations are even more expensive, and i want to use lsqnonlin, so i also dont know how to update X (which is easy for the Newton Raphson step if you know the Jacobian), so the suggestions made there dont help me for this case.
Matt J le 30 Juin 2023
Modifié(e) : Matt J le 30 Juin 2023
This seems to be a feasible workaround. So, the important thing to realize is that even though the iterative display says the Func-count=2, the call to the objective function is doing no significant work after the first function call, because the externally scoped stopflag has been raised by that point.
r=(x-10)^2+1; J=2*(x-10); %normal evaluation of residual function
r0=zeros(size(r)); %important that these be zero (but unclear why).
else %do no work