Time axis in netcdf files
Afficher commentaires plus anciens
Hello,
I am trying to build a netcdf file from an array but I have some problems in assigning the time scale.
This array (lon, lat, sea level pressure) was obtained by averaging monthly values from the original dataset, provided as a netcdf file.
Now, I need to create a new netcdf file with this annual values but I do not know how to assign the temporal information to my array.
Here there is the code I used:
clear all
%Open the monthly values netcdf file
ncid = netcdf.open('slp20c.nc','NC_NOWRITE');
[n0, x0, vD0, varAtt0] = netcdf.inqVar(ncid,0);
[n1, x1, vD1, varAtt1] = netcdf.inqVar(ncid,1);
[n2, x2, vD2, varAtt2] = netcdf.inqVar(ncid,2);
[n3, x3, vD3, varAtt3] = netcdf.inqVar(ncid,3);
varid0 = netcdf.inqVarID(ncid,'time');
varid1 = netcdf.inqVarID(ncid,'lon');
varid2 = netcdf.inqVarID(ncid,'lat');
varid3 = netcdf.inqVarID(ncid,'prmsl');
data0 = netcdf.getVar(ncid,0);
data1 = netcdf.getVar(ncid,1);
data2 = netcdf.getVar(ncid,2);
data3 = netcdf.getVar(ncid,3);
%Select data in the desired time range, Jan1871-Dec2007
data=data3(:,:,1:1644);
data=permute(data,[3 1 2]);
a=1:12:1644; b=12:12:1644;
%Compute the annual average of the field values
for i=1:length(a)
yearavg(i,:,:)=mean(data(a(i):b(i),:,:));
end
yearavg=permute(yearavg,[2 3 1]);
%Create new netcdf file with the values obtained in yearavg
nt=137; %nr of years
nx=51; %nr of longitude points
ny=46; %nr of latitude points
lon=310:2:410; lon=lon.';
lat=90:-2:0; lat=lat.';
time=[1871 1 1 0 0 0];
time=repmat(time,137,1);
year=1871:2007; year=year.';
time(:,1)=year;
time=datenum(time);
filenc='test.nc';
ncid = netcdf.create(filenc,'CLASSIC_MODEL');
dimid_lon = netcdf.defDim(ncid,'lon',nx);
dimid_lat = netcdf.defDim(ncid,'lat',ny);
dimid_time = netcdf.defDim(ncid,'time',nt);
varid_lon = netcdf.defVar(ncid,'lon','double',dimid_lon);
netcdf.putAtt(ncid,varid_lon,'long_name','Longitude')
netcdf.putAtt(ncid,varid_lon,'units','degree_e')
varid_lat = netcdf.defVar(ncid,'lat','double',dimid_lat);
netcdf.putAtt(ncid,varid_lat,'long_name','Latitude')
netcdf.putAtt(ncid,varid_lat,'units','degree_n')
varid_time = netcdf.defVar(ncid,'time','double',dimid_time);
netcdf.putAtt(ncid,varid_time,'long_name','Time')
netcdf.putAtt(ncid,varid_time,'units','month')
varid_slp = netcdf.defVar(ncid,'slp','double',[dimid_lon,dimid_lat,dimid_time]);
netcdf.putAtt(ncid,varid_slp,'long_name','slp')
netcdf.putAtt(ncid,varid_slp,'units','hPa')
netcdf.putAtt(ncid,varid_slp,'missing_value',-9999)
count=[nx ny nt];
start=[0 0 0];
netcdf.endDef(ncid)
netcdf.putVar(ncid,varid_slp,start,count,yearavg);
netcdf.close(ncid)
When I then open test.nc file, and I check the data, the new array seems to be correct, but all the longitude,latitude,time axes values are now fixed to a number (9.96920996838687e+36).
May anyone help? Thank you Isabella
Réponse acceptée
Plus de réponses (1)
Isabella
le 31 Oct 2011
0 votes
2 commentaires
Ashish Uthama
le 31 Oct 2011
Not familiar with that website to say anything specific. However, looking at the code pasted above, the actual time variable does not appear to be in the units claimed by its attribute (months). Maybe the website does some validity checks.
Isabella
le 1 Nov 2011
Catégories
En savoir plus sur NetCDF dans Centre d'aide et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!