Effacer les filtres
Effacer les filtres

Why is my matrix a scalar?

5 vues (au cours des 30 derniers jours)
Noya Linder
Noya Linder le 13 Juil 2023
Modifié(e) : Torsten le 13 Juil 2023
Hi, so I've been trying to create a Z matrix to plot using "surf":
Z = [];
x = 0;
for tt = T
x = x+1;
y = 0;
for rr = R
y = y+1;
Z(x, y) = j_nu(3, R(y), T(x), R, T, dRdt);
end
end
But Z ends up being a 1X1 matrix... what did I do wrong?
  2 commentaires
Stephen23
Stephen23 le 13 Juil 2023
Modifié(e) : Stephen23 le 13 Juil 2023
What are T and R ? Please give us all data required to run your code.
The obvious answer is that you only allocate data once to Z, e.g. this might occur if T and R are column vectors.
Noya Linder
Noya Linder le 13 Juil 2023
Yes, that was the problem. Thank you so much - I'm not used to working like this with vectors haha

Connectez-vous pour commenter.

Réponse acceptée

Noya Linder
Noya Linder le 13 Juil 2023
Modifié(e) : Torsten le 13 Juil 2023
Hi, the problem was I needed to convert my arrays to row vectors which I did by:
R = R.';
T = T.';
I don't know if this was the smartest way to do so but it works for me so thank you Stephen23 for pointing out that issue.
Also, thank you Nandini for pointing out my way of appointing values to Z was not efficient and showing me how it should be done. Have a great evening (or morning, wherever you are)!

Plus de réponses (0)

Catégories

En savoir plus sur Matrix Indexing dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by