i need to code speed ..anyone can help me? Getting rid of the loop would be a good start

v=[1 0 0 1];
d=[0.3 0 0 0.4]

d = 1×4

0.3000 0 0 0.4000

n="lp";
count=1;

gg=find(v)

gg = 1×2

1 4

clear b
g={'Cycle n.',count}

g = 1×2 cell array
    {'Cycle n.'}    {[1]}

j=1; %

j = 1

  for h=1:numel(gg)
    b{j,h}={[g,gg(h),d(gg(h))]};
  end
  

[Dyuman Joshi]

Why are you storing in such an awful manner?

It will be a nightmare to access any data from the output you have.

Also, what exactly it is that you want to store with this line of code -

{[g,gg(h),d(gg(h))]}

[pipor]

{'string',scalar,scalar}

i have to store an array of nxm ..how do you recommend to do it?

I wanted to avoid making a three dimensional array which would be too expensive as a resource

[pipor]

i want this: (m rows)

row 1 :'cycle x 1 0.2 'cycle y 4 0.5 .. .. for n columns

row 2 : 'cycle x 3 0.2 'cyclez 6 0.7 .. .. for n columns ..

[dpb]

This is absolutely incomprehensible as to what the end result is supposed to be from what inputs, sorry.

What you show in the last would be trivial as a table, particularly if n is constant.

But,

"I wanted to avoid making a three dimensional array which would be too expensive as a resource"

What makes you think a 3D array would be expensive? Depending upon what it actually is you're trying to do, it may be the most efficient storage and computationally as can be; MATLAB is specifically designed to operate on arrays from one to N-dimensional.

[pipor]

because I'm working on a laptop and on a lot of data it happened that I got the error about the memory..hence thinking about not making three-dimensional matrices

however I am modifying the code..maybe I make it clearer

[Bruno Luong]

But you have very bad start. This data organization is awful. We warn you, with such data you'll have speed, memory, and coding problems later.

Answer 1

[Bruno Luong]

clear
v=[1 0 0 1];
d=[0.3 0 0 0.4];
count=1;
gg=find(v);
g={'Cycle n.',count};
j=1;

clear b
for h=1:numel(gg)
    b{j,h}={[g,gg(h),d(gg(h))]};
end

% you want horrible code to store horrible data, here we go
bb = num2cell(num2cell([ repmat(g,[numel(gg) 1])  num2cell([ gg' d(gg)' ])], 2)');

isequal(bb,b)

ans = logical
   1

[pipor]

you want horrible code to store horrible data, here we go :D

thank but i write :"however I am modifying the code..maybe I make it clearer"

however I accept your work