What is wrong with this code.

2 vues (au cours des 30 derniers jours)
ZAINULABADIN ZAFAR
ZAINULABADIN ZAFAR le 11 Sep 2023
Commenté : Walter Roberson le 11 Sep 2023
% disp('%% -- Aufgabe 2.2.3 -- %%');
% Gitter erzeugen
[x y]=meshgrid([-2:0.05:2],0);
% Differentialgleichung
dx=x-x.^3;
ylim_extra=[-1/3 -1/3];
% Stabilitätsanalyse, Fixpunkte und zeitlicher Verlauf
[substatusflag,handle]=stabilitaetsanalyse(x,y,dx,zeros(size(y)),[],[],5,ylim_extra);
Unrecognized function or variable 'stabilitaetsanalyse'.
for i_count=2:4
set(handle(i_count),'XTick',[-2:2])
end
skizze_zeitverlauf(x,dx,5);
hold on % Analytische Lösung
t=0:0.05:2;
for startval=-2:0.25:2
C=(startval)/sqrt(1-startval^2);
plot(0,startval,'o','MarkerFaceColor',[0.75 0 0], ...
'MarkerEdgeColor',[0.75 0 0])
plot(t,exp(t)*C./sqrt(1+exp(2*t)*C^2), ...
'LineWidth',2,'Color',[0.75 0 0])
end
  5 commentaires
Dyuman Joshi
Dyuman Joshi le 11 Sep 2023
"Is it possible that you can provide the code in easy way...thanks in advance."
As I mentioned earlier - We can not help you with this. You should ask the author of the code for these functions.
Walter Roberson
Walter Roberson le 11 Sep 2023
The author of that code appears to be Dominik Zobel who was at dominik.zobel@tu-harburg.de
They posted code at a server that no longer exists.

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Réponses (1)

Sam Chak
Sam Chak le 11 Sep 2023
Modifié(e) : Sam Chak le 11 Sep 2023
Update: Thanks to @Walter Roberson for finding the source (PDF). The MATLAB functions stabilitaetsanalyse() and skizze_zeitverlauf() are unavailable. However, I tried to duplicate the results on page 3, section 2.2.3.
syms x(t) C
eqn = diff(x,t) == x - x.^3;
cond = x(0) == C; % initial value
xSol = dsolve(eqn, cond);
xSol = simplify(xSol)
xSol = 
c = -2:0.25:2; % range of initial values
for j = 1:numel(c)
xt = subs(xSol, C, c(j));
if c(j) >= 0
fplot( xt, [0 2], 'r'), hold on
else
fplot(-xt, [0 2], 'r'), hold on
end
end
hold off, grid on
xlabel('t')
ylabel('x(t)')

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