I have posted code below
A=[1;2;3;4;0;0;0;0]
for i=1:size(A)
if A(i)==0
A1= 'good'
else
A1= 'bad'
end
end
the output i get is
A1=bad
A1=bad
;
;
;
;
;A1=good
but i need to be dispalyed as
bad
bad
;
;
;
good
i know it is simple ,i tried but could not get the answer..plase help

 Réponse acceptée

Grzegorz Knor
Grzegorz Knor le 3 Nov 2011

0 votes

A=[1;2;3;4;0;0;0;0];
for i=1:size(A)
if A(i)==0
A1= 'good';
else
A1= 'bad';
end
disp(A1)
end

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