ExB drift velocity code equation

Hello, I would like to know if there is a better or more elegant way to code this equation and how I could get a better result? Not really sure. Any help will be appreciated. Thanks.

E = 0.1;
B = 20;

E = [0 0.1 0];
B = [0 0 20];

VE = cross(E,B)./B.^2

VE = 1×3

Inf NaN 0

Answer 1

[John D'Errico]

I might guess that what you really want is to divide by the square of the norm of B. NOT by the elements of B squared.

E = 0.1;
B = 20;
E = [0 0.1 0];
B = [0 0 20];
VE = cross(E,B)./norm(B)^2

VE = 1×3

0.0050 0 0