I got error in this script

3 vues (au cours des 30 derniers jours)
NANDEESWARAN
NANDEESWARAN le 3 Oct 2023
Modifié(e) : the cyclist le 3 Oct 2023
clear,clc,close all
datas = readtable('time_vs_load.xlsx','Sheet',2,'NumHeaderLines',1);
time = datas(:,1);
load = datas(:,2);
h = mean(diff(time));
n = length(load);
Error using tabular/length
Undefined function 'LENGTH' for input arguments of type 'table'. Use the height, width, or size functions instead.
% Peak Loading Rate Using Central Difference formula
peak_l_r =(-3*load(1) + 4*load(2) - load(3))/(2*h);
for i = 2:n-1
peak_l_r = (load(i+1)-load(i-1))/(2*h);
end
peak_l_r = (load(n-2)-4*load(n-2) + 3*load(n))/(2*h);
peak_l_r = max(peak_l_r)
pear_loading_rate = peak_l_r
% Impulse during the entire timeseries using Trapezoidal methods
impulse = trapz(time,load)
% Results
disp(['Peak loading rate: ', num2str(peak_loading_rate)]);
disp(['Impulse: ', num2str(impulse)]);

Réponse acceptée

the cyclist
the cyclist le 3 Oct 2023
Modifié(e) : the cyclist le 3 Oct 2023
The line
time = datas(:,1);
will give a table with one variable. You need to use curly brackets in access the contents of the table column.
time = datas{:,1};
This code works (after I fixed the typo "pear_loading_rate"):
clear,clc,close all
datas = readtable('time_vs_load.xlsx','Sheet',2,'NumHeaderLines',1);
time = datas{:,1};
load = datas{:,2};
h = mean(diff(time));
n = length(load);
% Peak Loading Rate Using Central Difference formula
peak_l_r =(-3*load(1) + 4*load(2) - load(3))/(2*h);
for i = 2:n-1
peak_l_r = (load(i+1)-load(i-1))/(2*h);
end
peak_l_r = (load(n-2)-4*load(n-2) + 3*load(n))/(2*h);
peak_l_r = max(peak_l_r)
peak_l_r = -1.6280e+04
peak_loading_rate = peak_l_r
peak_loading_rate = -1.6280e+04
% Impulse during the entire timeseries using Trapezoidal methods
impulse = trapz(time,load)
impulse = 884.2424
% Results
disp(['Peak loading rate: ', num2str(peak_loading_rate)]);
Peak loading rate: -16280.0583
disp(['Impulse: ', num2str(impulse)]);
Impulse: 884.2424
  1 commentaire
NANDEESWARAN
NANDEESWARAN le 3 Oct 2023
Thanks sir. I appreciate your help

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