numbering equal to 1 if the number is different from the previous one

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Luca Re
Luca Re le 3 Oct 2023
Commenté : Luca Re le 3 Oct 2023
the first element >0 i assign =1
in the subsequent elements if the number is different from the previous one then I put =1.. otherwise =0
a=[0 2 2 2 3 3 3 3 4 4 5 6 6 7 8 9 9 9 9 9 ]
[0 1 0 0 1 0 0 0 1 0 1 1 0 1 1 1 0 0 0 0]
[SL: edited to pull the text out of the code segment.]
  3 commentaires
Torsten
Torsten le 3 Oct 2023
Hint:
You could try "diff" for a solution.

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