using find function for char

line =

    10    L1    L2    L5    C1    C2    P2    C5    S1    S2# / TYPES OF OBSERV

Name Size Bytes Class

line 1x81 162 char

%I need to use find function for each character in line. For example, I need to know which column is L1 or L2.

Answer 1

[Guillaume]

Do you actually want to find which column of the string where L1 and L2 are, or if L1 is the second element and L2 the third?

If the former, then use Michael's answer. If the latter, then the best thing to do would be to split the string at the whitespaces then use strcmp:

line = '10    L1    L2    L5    C1    C2    P2    C5    S1    S2# / TYPES OF OBSERV'; 
splitline = strsplit(line);
L1idx = find(strcmp(splitline, 'L1'))
L2idx = find(strcmp(splitline, 'L2'))

[sermet]

I need to know which column, for example the answer for L1 must be 2 and for L2 it is 3 if we assume line as a 1*10 (one row, 10 columns) matrix.

When I perform strsplit(line) there are 2 unnecessary characters ('') was added to the line thus the result was wrong.

[Guillaume]

So, not the character position as in Michael answer

In that case, my answer is what you want.

[sermet]

In my case, your answer is related the topic but as I wrote in my comment the result was wrong.

[Guillaume]

I cannot reproduce your problem with the example given. My answer gives me 2 and 3 as output.

Can you find out the ASCII value of the extra characters, as it's not obvious what they are from your comment. You can get the ASCII value of a character by converting it to double, eg:

c = 'A';
asciival = double(c)  %should return 65

Answer 2

[Michael Haderlein]

line='10    L1    L2    L5    C1    C2    P2    C5    S1    S2';

strfind(line,'L2')

ans =

      13