piecewise function and function handles

Hi everybody, I have a little trouble issues with my function handles.

In particular I am trying to describe a function handle which has a specific value (related to two variables) in a range of one of the two vairables, and 0 otherwise.

E_2rad=0.79;

@(freq_wave,wave_angle) (0<= wave_angle <= pi-E_2rad) .* ((2.25/4)*ro_w*g*B*0.75).*(sin(E_2rad+wave_angle).^2+(2.*freq_wave.*(vel_nave/g).*(cos(E_2rad).*cos(E_2rad+wave_angle)...

-cos(wave_angle)))) + (wave_angle > pi-E_2rad) .* 0

the function written as above mentioned returns a value different from 0 if wave_angle > pi-E_2rad instead and I cannot understand why and how to fix it. Thanks in advance for your help

Answer 1

[Dyuman Joshi]

You need to define multiple conditions separately/individually i.e -

This

(0<= wave_angle <= pi-E_2rad)

should be -

(wave_angle >=0) && (wave_angle <= pi-E_2rad)

[Gianluca Angelini]

Hi Dyuman: thanks again for your support.

in this case, I decided to avoid your solution because, after the definition of this function handle i need to sum it with other function handles and integrate them. In fact, after calling a double integration and after separating the multiple conditions, this message appears:

Operands to the || and && operators must be convertible to logical scalar values.

any other suggestion to solve this other trouble?

[Dyuman Joshi]

A silly mistake from my side - It should be a single ampersand i.e. & .

If there is still an error after making the aforementioned change, please share your code and state the error you get.

[Gianluca Angelini]

Don't worry. You couldn't have known about integrals.

By the way all the problems aforementioned are fixed. Thanks again!

[Dyuman Joshi]

The anonymous function is vectorized and so, for the given comparison, I should have noted that it should be a single ampersand. (I really should be going to sleep earlier :P)

Nonetheless, glad to know that your issue is solved. Happy to have helped!