Creating a "clock" plot, like polarplot.

9 vues (au cours des 30 derniers jours)
dormant
dormant le 27 Déc 2023
Commenté : Dyuman Joshi le 30 Déc 2023
Is it possible to create a polar-like plot or histogram where the theta values are in minutes between 0 and 60?
I can do it by converting the values to radians and setting the labels, but it would be less-error prone if the theta scale was settable (ThetaLim doesn't do this).
WT = [ 1 2 3 5 42 43 59.5 0.5];
theta = deg2rad( WT*6 );
edges = deg2rad(-5:10:355);
figure;
pax = polaraxes;
polarhistogram( theta, edges );
pax.ThetaDir = 'clockwise';
pax.ThetaZeroLocation = 'top';
pax.ThetaTick = [0 90 180 270 360];
pax.ThetaTickLabel = [0 15 30 45 60];
pax.RTick = [];
  1 commentaire
Dyuman Joshi
Dyuman Joshi le 30 Déc 2023
@dormant, The method you've come up with seems like a good approach.
I think the (accepted) answer does not understood or acknowledge what the expected output is.

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Réponse acceptée

Hassaan
Hassaan le 27 Déc 2023
Déplacé(e) : Voss le 27 Déc 2023
WT = [ 1 2 3 5 42 43 59.5 0.5];
theta = deg2rad(WT*6);
edges = deg2rad(-0.5:1:60.5);
figure;
pax = polaraxes;
polarhistogram(theta, edges);
pax.ThetaDir = 'clockwise';
pax.ThetaZeroLocation = 'top';
pax.ThetaTick = [0 90 180 270 360];
pax.ThetaTickLabel = {'0' '15' '30' '45' '60'};
pax.RTick = [];
The code snippet provided is a good starting point and, with a few adjustments, it should be able to produce a reliable and accurate clock-like polar histogram plot.
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If you find the solution helpful and it resolves your issue, it would be greatly appreciated if you could accept the answer. Also, leaving an upvote and a comment are also wonderful ways to provide feedback.
  1 commentaire
dormant
dormant le 28 Déc 2023
Many thanks. I'll try and write it as a function for future use.
I will try and include an option to produce a polar stem plot instead of a polar histogram, because the latter is often over-emphatic.

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