Warning using integral function: Function behaves unexpectedly on array inputs

fplot(@(E) Current(E))

Current(1)

function test_integral = Current(V)

    test_integral = integral(@(E) temp(E,V), -inf, inf);

    function tempf = temp(E,V)

        tempf = V.*exp(-(E.^2));

    end
end

This is basically my code. Running this gives an error message of

Warning: Function behaves unexpectedly on array inputs. To improve performance, properly vectorize your function to return an output with the same size and
shape as the input arguments. 
> In matlab.graphics.function.FunctionLine>getFunction
In matlab.graphics.function/FunctionLine/updateFunction
In matlab.graphics.function/FunctionLine/set.Function_I
In matlab.graphics.function/FunctionLine/set.Function
In matlab.graphics.function.FunctionLine
In fplot>singleFplot (line 245)
In fplot>@(f)singleFplot(cax,{f},limits,extraOpts,args) (line 200)
In fplot>vectorizeFplot (line 200)
In fplot (line 166)
In test4 (line 4) 

I think this has something to do with the integral function and fplot function colliding, but I don't know how any of the two functions can be substituted. Perhaps there is a way to vectorize the results of the Current function? Again, I don't know if this is even the right direction.

Help would be very much appreciated. Thanks in advance.

Answer 1

[Dyuman Joshi]

Set the 'ArrayValued' property to 1 for the integral, so that it evaluates the integral of an array/vector valued function/integrand.

Current(1:4)

ans = 1×4

1.7725 3.5449 5.3174 7.0898

fplot(@(E) Current(E))

function test_integral = Current(V)

    test_integral = integral(@(E) temp(E,V), -inf, inf, 'ArrayValued', 1);

    function tempf = temp(E,V)

        tempf = V.*exp(-(E.^2));

    end
end

[DONGUK KIM]

It worked! Thanks a lot

[Dyuman Joshi]

You're welcome!