- For scalar values && is (in general) faster than & because it only evaluates the right argument if the left argument is TRUE.
- Defensive programming: by using && you assert that its arguments are scalar. If later they are erroneously not scalar then && will stop with an error (rarher than continuing in some unknown state).
- Clarity to the reader
using "&" with logical array
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oN is a array Logical
col is array Logical
why is not correct using &?
K>> class(oN)
ans =
'logical'
K>> class(col)
ans =
'logical'
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/1615973/image.png)
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Stephen23
le 13 Fév 2024
Modifié(e) : Stephen23
le 13 Fév 2024
"why is not correct using &?"
Who says that it is not "correct" ? What you show is not a code error (underlined in red), it is a recommendation (underlined in orange)
Benefits:
If you want to ignore this recommendation then right-click and select one of the "ignore" options.
3 commentaires
Stephen23
le 13 Fév 2024
Modifié(e) : Stephen23
le 13 Fév 2024
"The array is a logical type so the correct use of the operator is to use the "&" for logical operations.
You just invented that rule yourself: there is no rule saying that scalar values must use &.
In contrast the static code parser is written by the people who actually develop MATLAB.
""&&" if they are scalars but this is not the data type in question"
MATLAB does not have a "scalar" data type, they are all arrays:
Most likely the data in question is scalar: assuming that k is a scalar subscript then both of the arguments to && will be scalar, and the recommendation is completely appropriate. That is most likely what the static parser has detected. Your invention of non-existent data types and non-existent rules does not help you.
Question: what size do oN(k) and col(k) have?
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