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Plot graph form satellite position

5 vues (au cours des 30 derniers jours)
Toshi
Toshi le 19 Mar 2024
I am using TLE file of satellite to extract the position and velocity. I want to plot the graph for the same but i am getting error while doing so. Here i am using timetable to plot the graph.
startTime = datetime(2024,3,1,12,38,08);
stopTime = datetime(2024,3,5,15,38,08);
sampleTime = 7200;
sc = satelliteScenario(startTime,stopTime,sampleTime);
tleFile = "o3b.tle" ;
sat1 = satellite(sc,tleFile, ...
"Name","sat1", ...
"OrbitPropagator","sgp4");
elements1 = orbitalElements(sat1);
[position,velocity]= states(sat1);
t=datetime(2024,3,1,12,38,08):datetime(2024,3,5,15,38,08);
TT = array2timetable(position,'RowTimes',t);
plot(TT.t,TT.position);
xlabel("Time")
ylabel("Relative position (km)")
legend("Sat2","Sat3")

Réponses (1)

Himanshu
Himanshu le 22 Mar 2024
Hello,
I understand that you are using MATLAB to work with satellite data, specifically by creating a satellite scenario, loading a satellite from a TLE file, and plotting its position over time.
Since more information about the "o3b.tle" file is not available, I assume the error might have occurred while creating the time vector.
The attempt to create a vector of datetime objects using datetime(2024,3,1,12,38,08):datetime(2024,3,5,15,38,08) might not work as expected because you're trying to create a vector without specifying the step size.
To resolve the issue, you can replace this with the following code:
t = datetime(2024,3,1,12,38,08):seconds(sampleTime):datetime(2024,3,5,15,38,08);
I hope this helps.

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