How to erase a specific elements for the name of string values and then replace them?
4 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
Ahmad Al-Issa
le 17 Avr 2024
Modifié(e) : Ahmad Al-Issa
le 18 Avr 2024
Hello everyone,
I have names of values in this form:
dd_mm_yy_hh_mm_ss
for example:
Temp_06_02_24_10_39_34 = 32;
I would like to select only the number for the month (02) and replace it with the coresponding name of month in order to creat new value, for example:
Temp_Feb = 32;
How can I do this ?
Best regards, Ahmad
3 commentaires
Stephen23
le 17 Avr 2024
Modifié(e) : Stephen23
le 17 Avr 2024
Very bad data design has meta-data (e.g. dates) in variable names. Such badly-designed data will force you into writing slow, complex, inefficient, obfuscated code that is fragile/buggy and hard to debug. Best avoided:
Learn to use arrays.
Réponse acceptée
Adam Danz
le 17 Avr 2024
Modifié(e) : Adam Danz
le 17 Avr 2024
Assumptions:
- "Temp_06_02_24_10_39_34 = 32"; is a string
- This is not a variable name
- The month is in the 2nd numeric position (02, above)
- The goal is to replace the entire day_month_year_hour_minute_second datetime with the 3-letter abbreviation for the month.
str = "Temp_06_02_24_10_39_34 = 32;";
% Extract the month number and convert to short month name
[~,dtParts] = regexp(str, '_(\d+)','match','tokens');
monthStr = month(datetime(str2double([dtParts{:}])),'shortname');
% Replace the datetime portion with the short month name
newStr = regexprep(str, '(_\d+){6}',['_',monthStr{1}])
4 commentaires
Stephen23
le 18 Avr 2024
Here is an approach using a dynamic regular expression. This avoids the extra REGEXP and MONTH function calls.
str = "Temp_06_02_24_10_39_34 = 32;";
fnh = @(s)char(datetime(s,'InputFormat','_dd_MM_yy_hh_mm_ss','Format','MMM'));
new = regexprep(str,'(_\d+){6}','_${fnh($0)}')
Plus de réponses (1)
Jon
le 17 Avr 2024
I would suggest in general that you not embed the date time data in the variable name. Instead use a table, timetable, or some other data structure to hold these values along with the temperatures. Here's a little example using just a MATLAB table
% Make example table to hold data
yyyy = [2023,2023,2023,2024]'
mm = [8,4, 2, 3 ]'
dd = [15,18,6, 2]'
hh = [9,13,8,23]'
mi = [15,18,59,42]'
sec = [11,22,19,49]'
T = [29,15.3,22, 36.4]'
time = datetime(yyyy,mm,dd,hh,mi,sec);
Tdata = table(time,T)
% Find the temperature for February (month = 2)
idl = month(Tdata.time) == 2;
Tdata.T(idl)
9 commentaires
Jon
le 17 Avr 2024
Here is an approach for extracting the month from a string with day month year ..and then creating a new string with just the month
s1 = 'Temp_15_05_24_10_44_22'
time = datetime(s1(6:end),'InputFormat','dd_MM_yy_HH_mm_ss')
mname = month(time,"shortname");
s2 = "Temp_" + mname{1}
Voir également
Catégories
En savoir plus sur Whos dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!